The pressure inside the can upon cooling is 0.4 atm.
<u>Explanation:</u>
Given -
Initial Temperature, T1 = 908°C = 908 + 273 K = 1181 K
Final Temperature, T2 = 208°C = 208 + 273 K = 481 K
Pressure upon cooling, P2 = ?
Using Gay Lussac's law:
P1/T1 = P2/T2
P2 = P1 X T2 / T1
P2 = 1 atm X 481 / 1181
P2 = 0.4 atm
Therefore, the pressure inside the can upon cooling is 0.4 atm.
Answer:
true
Explanation:
shear strain is define as the ratio of change in deformation to the original length perpendicular to the axes of member due to shear stress.
ε = deformation/original length
strain is a unit less quantity but shear stain is generally expressed in radians but it can also be expressed in degree.
