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Irina18 [472]
3 years ago
7

PLEASE HELP URGENT! this is a homework that is due today but I forgot to do it please help those 2 questions!

Physics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

balanced unbalanced balanced balanced

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alexdok [17]

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It's Laws of Motion

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6 0
3 years ago
Question 1
Agata [3.3K]

Answer:

Hypothesis:

The amount of limestone that dissolves in the acid is directly proportional to the concentration of acid used.

Explanation:

Acids dissolve limestone according to the following general equation;

2HX(aq) + CaCO3(s) -------> CaX2(aq) + H2O (l) + CO2(g). Where HX represents any acid at all.

This dissolution process is a chemical reaction. It was experimentally observed that the amount of limestone that dissolved in acid depends on the concentration of acid. Various concentrations of acid were then prepared and a particular mass of limestone was dissolved in each concentration of acid. The amount of limestone dissolved in each case was carefully noted.

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3 0
4 years ago
For the circuit shown, R = 75.0 ohms, L= 55.0 mg, and C = 25.0 μC. The power source has 12.0 V arms and a frequency of 60.0 Hz.
Natasha_Volkova [10]

Explanation:

Given that,

Resistance R = 75.0 ohms

Inductance L = 55.0 mH

Capacitance C = 25.0\ \mu C

Voltage V = 12.0 V

Frequency f = 60.0 Hz

We need to calculate the angular frequency

Using formula of angular frequency

\omega = 2\pi f

Put the value into the formula

\omega =2\times3.14\times60.0

\omega=376.8\ rad/s

(a). We need to calculate the  value of X_{L}

Using formula of X_{L}

X_{L}=\omega\times L

Put the value into the formula

X_{L}=376.8\times55.0\times10^{-3}

X_{L}=20.724\ \Omega

(b). We need to calculate the  value of X_{L}

Using formula of X_{C}

X_{C}=\dfrac{1}{\omega C}

X_{C}=\dfrac{1}{376.8\times25.0\times10^{-6}}

X_{C}=106.16\ \Omega

(c). We need to calculate the value of Z

Using formula of impedance

Z=\sqrt{R^2+(X_{L}-X_{C})^2}

Put the value into the formula

Z=\sqrt{75.0^2+(20.724-106.16)^2}

Z=113.68\ \Omega

(d). We need to calculate the rms current

Firstly we need to calculate the current

Using formula of current

I=\dfrac{V}{R}

Put the value into the formula

I=\dfrac{12.0}{75.0}

I=0.16\ A

Using formula of rms current

I_{rms}=\dfrac{I_{0}}{\sqrt{2}}

I_{rms}=\dfrac{0.16}{\sqrt{2}}

I_{rms}=0.113\ A

(e). We need to calculate the rms voltage across the resistor

Using formula of rms voltage

V_{rms}=I_{rms}\times R

V_{rms}=0.113\times75.0

V_{rms}=8.475\ V

(f). We need to calculate the rms voltage across the inductor

Using formula of rms voltage

V_{rms}=I_{rms}\times X_{L}

V_{rms}=0.113\times20.724

V_{rms}=2.342\ V

(g). We need to calculate the rms voltage across the capacitor

Using formula of rms voltage

V_{rms}=I_{rms}\times X_{C}

V_{rms}=0.113\times106.16

V_{rms}=11.99\ V

(h).  We need to calculate the dissipated power by the circuit

Using formula of dissipated power

P=RI^2

Put the value into the formula

P=75.0\times0.113^2

P=0.958\ W

Hence, This is the required solution.

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