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gregori [183]
1 year ago
5

A container built for transatlantic shipping is constructed in the shape of a right rectangular prism. Its dimensions are 7 ft b

y 5 ft by 8.5 ft. The container is entirely full. If, on average, its contents weigh 0.21 pounds per cubic foot, and, on average, the contents are worth $8.80 per pound, find the value of the container’s contents. Round your answer to the nearest cent.
Mathematics
1 answer:
____ [38]1 year ago
7 0

Given:

Dimensions are 7 ft by 5 ft by 8.5 ft

Contents weigh 0.21 pound

Contents worth $8.80 per pound

Find-: value of container contents.

Sol:

Volume is:

\begin{gathered} Volume\text{ = }7\times5\times8.5 \\  \\ =297.5 \end{gathered}

The formula of density is:

\text{ Density =}\frac{\text{  Mass}}{\text{ Volume}}

So,

\begin{gathered} 0.21=\frac{\text{ Weight  of contents in container}}{\text{ Volume of container}} \\  \\ 0.21=\frac{\text{ Weight}}{297.5} \\  \\ 0.21\times297.5=\text{ Weight} \\  \\ \text{ Weight of contents in container = }62.475\text{ Pound} \end{gathered}

Now $8.80 per pound

For 62.475 pounds the value is:

\begin{gathered} =62.475\times8.80 \\  \\ =549.78 \end{gathered}

So the value of the container contents is 549.78

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So, using the equation of mid-point,

h=\frac{x_{1}+x_{2}}{2}  and  k=\frac{y_{1}+y_{2}}{2}

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3 years ago
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