A neon light consists of a glass tube with metal wires at each end. When connected to a high-voltage source, the gas glows.

Physics

2 answers:

Pavlova-9 [17]4 years ago

4 0

C

Glass is an insulator

Tatiana [17]4 years ago

3 0

If a flay lands on the glass tube, it will most likely, C) The fly will not feel a shock because the glass insulates it from the electrons in the gas and the metal.

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An automobile can be considered to be mounted on four identical springs as far as vertical oscillations are concerned. The sprin

iogann1982 [59]

Answer:

Therefore, the spring constant of each spring = 1.6 × 10⁻⁶ kg/s².

Explanation:

The period (T) of a spring in oscillation = 2π √(m/k)............. equation 1

Where m = mass acting on the spring (kg), k = spring constant of the spring (kg/s²).

Making k the subject of equation 1

k = T²/(4π²×m) .......................... equation 2

From the question, F = 4.42 Hz,

since T = 1/F

then, T = 1/F = 1/4.42 =0.226 s, π = 3.143

since the weight of the mass is evenly distributed over the four identical spring, Hence

m = 1450/4 = 362.5 kg

Substituting these values into equation 2

k = 0.226/{(4×3.143²)362.5}

k = 0.226/(14323.751)

k = 0.0000016 kg/s²

k = 1.6 × 10⁻⁶ kg/s².

Therefore, the spring constant of each spring = 1.6 × 10⁻⁶ kg/s².

5 0

3 years ago

A wheelbarrow is experiencing two forces. One is pushing 5 N to the east and the other 5 N in the exact opposite direction. What

mezya [45]

Assuming no other forces are acting on the wheelbarrow, it must be stationary.

4 0

3 years ago

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If an astronaut weighs 900 n on earth, what does he weigh on the planet venus?

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Use w=m*g value of g is 1.67m/s^2

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Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and ex

Ahat [919]

The question is incomplete. The complete question is :

Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.

What is the frequency of the sound?

Solution :

Given :

The distance between the two loud speakers, $d = 1.8 \ m$