3 years ago

How to solve 30(a) Give solution asap.

Physics

1 answer:

expeople1 [14]3 years ago

5 0

Answer:

They will not meet

h-hX=1.2*g*t²

hX=v0*t-(1/2*g*t²)

Explanation:

fall h=1/2*g*t²

elevation time if v0=20 m/s te=v0/g=20 m/s /9.81 m/s²=2.0387s

hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m

free fall

t=2.0387s yields hX=1/2*g*t²=20.387 m

h-hX=200m - 20.387 m=179,613 m.

so, the second body has not enough initianoal speed to reach a meeting point

You might be interested in

In a mall, a shopper rides up an escalator between floors. At the top of the escalator, the shopper turns right and walks 6.40 m

Elden [556K]

Answer:

25 degrees above the horizontal.

5 0

2 years ago

A QL = -26 μC charge is placed on the x-axis at x = - 0.2 m. A QR = 26 μC charge is placed at x = +0.2 m. (for all answers below

Kaylis [27]

<span>You are given a QL = -26 μC charge that is placed on the x-axis at x = - 0.2 m and a QR = 26 μC charge that is placed at x = +0.2 m. The answers are:

The x-component of the electric field at x = 0 m and y = 0.2 m is 3.
The y-component of the electric field at x = 0 m and y = 0.2 m is 2.

</span>

4 0

2 years ago

What is the differ of fermentation from respirstion

Andrej [43]

This may help u... :P