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3 years ago

What forms when two of earths plates pull apart

Physics

2 answers:

kakasveta [241]3 years ago

6 0

Answer:becomes a earth quake

Explanation:When to plates pull apart it makes a movement in the tectonic plate and makes a earthquake

zhannawk [14.2K]3 years ago

3 0

Answer: (Screen Shot)

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What happens during the fourth stage of technological design that is not necessary during the sixth or seventh stages of scienti

riadik2000 [5.3K]

<span>A design is remodeled after analysis and tested again.</span>

8 0

2 years ago

Read 2 more answers

In a standard tensile test a steel rod of 22-mm diameter is subjected to a tension force of 75kN. Knowing that v = 0.30 and E =

VladimirAG [237]

Answer:

(a) Elongation of rod = 0.19732 mm

(b) Change in diameter = 0.00651 mm

Explanation:

Circular area at end of steel rod = pi * diameter^2 / 4

$Area = pi * (22 * 10^-^3)/4$

Area = 3.801 * 10^(-4) meter squared

Stress = force / area

Stress = 75000 / (3.801 * 10^-4)

Stress = 197316495 Pa OR 0.197 GPa

Modulus of elasticity = stress / strain

200 = 0.19732 / Strain

Strain = 0.0009866 (longitudinal)

(a) Strain = change in length / initial length

0.0009866 = Elongation of rod / 200

Elongation of rod = 0.19732 mm

(b) Poisson ratio = lateral strain / longitudinal strain

0.3 = lateral strain / 0.0009866

Lateral strain = 0.000296

Lateral strain = Change in diameter / original diameter

0.000296 = Change in diameter / 22

Change in diameter = 0.00651 mm

4 0

3 years ago

Read 2 more answers

A string under a tension of 68 N is used to whirl a rock in a horizontal circle of radius 3.7 m at a speed of 16.53 m/s. The str

alekssr [168]

Answer:

$F = 5253.7 N$

Explanation:

As we know that tension force in the string will be equal to the centripetal force on the string

so we will have

$T = \frac{mv^2}{L}$

now we have

$68 = \frac{m(16.53^2)}{3.7}$

now we have

$68 = 73.8 m$

$m = 0.92 kg$

now when string length is 0.896 m and its speed is 71.5 m/s then we will have

$F = \frac{mv^2}{r}$

$F = \frac{0.92(71.5^2)}{0.896}$

$F = 5253.7 N$

8 0

3 years ago

Read 2 more answers

ΔP = 1.88 x 10^4 Pa. Use this answer to estimate the volume flow rate of blood from the head to the feet of a six-foot-tall pers

Sveta_85 [38]

Answer: $3765.66 \frac{m^{3}}{s}$

Explanation:

We can solve this problem using the <u>Poiseuille equation</u>:

$Q=\frac{\pi r^{4}\Delta P}{8\eta L}$

Where:

$Q$ is the Volume flow rate

$r=23 cm \frac{1 m}{100 cm}=0.23 m$ is the effective radius

$L=6 ft \frac{0.3048 m}{1 ft}=1.8288 m$ is the length

$\Delta P=1.88(10)^{4} Pa$ is the difference in pressure

$\eta=3(10)^{-3} Pa.s$ is the viscosity of blood

Solving:

$Q=\frac{\pi (0.23 m)^{4}(1.88(10)^{4} Pa)}{8(3(10)^{-3} Pa.s)(1.8288 m)}$

$Q=3765.66 \frac{m^{3}}{s}$

7 0

3 years ago

A motorcycle together with its Rider with 150 kg how much work is needed to set its movement at 15 metre per second.

AVprozaik [17]

Answer:

W = 16875 J

Explanation:

We have,

Mass of a motorcycle together with its rider is 150 kg

It is required to find the work is needed to set its movement at 15 metre per second. The work done is given by :

$W=\dfrac{1}{2}mv^2$

Plugging all the values in above formula such that :

$W=\dfrac{1}{2}\times 150\times (15)^2\\\\W=16875\ J$

So, the work of 16875 J is needed.

5 0

2 years ago