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sdas [7]
1 year ago
5

two tugboats pull a disabled supertanker. each tug exerts a constant force of 2.20×106 n , one at an angle 19.0 ∘ west of north,

and the other at an angle 19.0 ∘ east of north, as they pull the tanker a distance 0.890 km toward the north.
Physics
1 answer:
asambeis [7]1 year ago
7 0

The amount of work the two tugboats completed on the supertanker W = 3.12 × 10^9 joules .

Work is a physics term used to describe the energy transfer that takes place when an object is moved over a distance by an external force, at least some . The component of the force acting along the path multiplied by the length of the path can be used to calculate work if the force is constant. Mathematically, this idea is expressed as W = fd, where W is the work and f is the force multiplied by d, the distance. Work is completed when the force is applied at an angle of with respect to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as other methods.  However, the work is thought to be negative if the applied force is in opposition to the item's motion, indicating that energy is being pulled away from the object

Learn more about work here:

brainly.com/question/1374468

#SPJ4

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You push on a cart (18.0kg) at a 30 degree below horizontal angle. The coefficient of kinetic friction between the chair and the
podryga [215]

Given that force is applied at an angle of 30 degree below the horizontal

So let say force applied if F

now its two components are given as

F_x = Fcos30


F_y = Fsin30


Now the normal force on the block is given as

N = Fsin30 + mg

N = 0.5F + (18\times 9.8)

N = 0.5F + 176.4

now the friction force on the cart is given as

F_f = \mu N

F_f = 0.625(0.5F + 176.4)

F_f = 110.25 + 0.3125F

now if cart moves with constant speed then net force on cart must be zero

so now we have

F_f + F_x = 0

Fcos30 - (110.25 + 0.3125F) = 0

0.866F - 0.3125F = 110.25

F = 199.2 N

so the force must be 199.2 N

8 0
3 years ago
Bernie drove home from a vacation in 1.5 hours. He traveled a total distance of 60 miles. What was his average speed in miles pe
mafiozo [28]

Answer: 40

Explanation:

I believe this is correct. I did 60/1.5 to get 40/mph

6 0
4 years ago
Read 2 more answers
A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this p
olya-2409 [2.1K]

Answer:

Acceleration of proton will be a=0.67\times 10^{11}m/sec^2

Explanation:

We have given a proton is placed in an electric field of intensity of 700 N/C

So electric field E = 700 N/C

Mass of proton m=1.67\times 10^{-27}kg

Charge on proton e=1.6\times 10^{-19}C

So electric force on the proton F=qE=1.6\times 10^{-19}\times 700=1.120\times 10^{-16}N

This force will be equal to force due to acceleration of the proton

According to newton's law force is given by F = ma

So 1.67\times 10^{-27}\times a=1.120\times 10^{-16}

a=0.67\times 10^{11}m/sec^2

So acceleration of proton will be a=0.67\times 10^{11}m/sec^2

6 0
4 years ago
Assuming a roughly spherical shape and a density of 4000 kg/m3, estimate the diameter of an asteroid having the average mass of
vredina [299]

Explanation:

It is given that,

Density of asteroid, \rho=4000\ kg/m^3

Mass of asteroid, m=10^{17}\ kg

We need to find the diameter of the asteroid. The formula of density is given by:

\rho=\dfrac{m}{V}

V is the volume of spherical shaped asteroid, V=\dfrac{4}{3}\pi r^3

r^3=\dfrac{3M}{4\pi \rho}

r^3=\dfrac{3\times 10^{17}\ kg}{4\pi \times 4000\ kg/m^3}

r^3=\sqrt{5.96\times 10^{12}}

r = 2441311.12 m

Diameter = 2 × radius

d = 4882622.24 m

or

d=4.88\times 10^6\ m

Hence, this is the required solution.

8 0
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Which layer of the atmosphere do most planes fly in?
melomori [17]

Answer:

It is the Stratosphere.

Explanation:

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