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motikmotik
3 years ago
13

Does Radiation Affects this question? If it doesn't, is the answer C?​

Physics
1 answer:
kotegsom [21]3 years ago
5 0
The answer will be C
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If the mass of a moving object were quartered, it’s inertia would be
AVprozaik [17]

Answer:

Quartered

Explanation:

Because you're a liberal.

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2 years ago
Both Newton's Law of Universal Gravitation and Coulomb's Law follow the ...
Romashka [77]

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inverse square relationship

Explanation:

Both the Newton's law of universal gravitation and coulomb's law have their force inversely proportion to the square of the distance between the bodies.

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2 years ago
A graph shows how the temperature of a substance changes as energy is added steadily over time.
OlgaM077 [116]

Answer:

A flat, horizontal line  

Explanation:

A flat, horizontal line indicates a phase change.

The temperature does not increase because the added heat goes into converting one phase into another.

A is wrong. A downward-sloping line indicates that the temperature is decreasing with time.

C is wrong. An upward-sloping line indicates that the temperature is increasing with time.

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3 years ago
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The diagram below shows a periodic wave. Which two points on the wave are 180 degrees out of phase?
Ksju [112]

Answer:

A and C are 180 deg out of phase (opposite points on a 360 deg wave)

3 0
3 years ago
A car moving at a speed of 36 km/h reaches the foot of a smooth
boyakko [2]

Answer:

d = 10.2 m

Explanation:

When the car travels up the inclined plane, its kinetic energy will be used to do the work in climbing up. So according to the law of conservation of energy, we can write that:

Kinetic\ Energy\ of\ the \ Car = Work\ Done\ while\ moving\ up\ the\ plane\\\frac{1}{2}mv^{2} = Fd

where,

m = mass of car

v = speed of car at the start of plane = (36 km/h)(1000 m/1 km)(1 h/3600 s)

v = 10 m/s

F = force on the car in direction of inclination = W Sin θ

W = weight of car = mg

θ = Angle of inclinition = 30°

d = distance covered up the ramp = ?

Therefore,

\frac{1}{2}mv^{2} = mgdSin\theta\\\frac{1}{2}v^{2} = gdSin\theta\\\frac{1}{2}(10\ m/s)^{2} = d(9.81\ m/s^{2}) Sin\ 30^{0}

<u>d = 10.2 m</u>

4 0
2 years ago
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