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1 year ago

What are the 3 Earth's internal heat?.

1 answer:

3 0

There are three primary sources of interior heat: (1) heat from the planet's formation and accretion, which has not yet been lost; (2) frictional heating brought on by the planet's denser core material sinking to the center; and (3) heat from radioactive element decay.

<h3>What is a brief explanation of heat?</h3>

Heat is the movement of kinetic energy from a source of energy to a medium or an object, or vice versa. Absorption, conduction, & convection are the three possible pathways for this energy conversion.

<h3>What is heat in reality?</h3>

In solids, liquids, and gases, the movement of microscopic particles known as atoms, molecules, or ions produces heat energy. One thing can impart heat energy onto another.

To know more about Heat visit:

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You might be interested in

A parallel-plate capacitor is constructed from two 6.0 cm × 6.0 cm electrodes spaced 1.5 mmapart. The capacitor plates are charg

Brilliant_brown [7]

A) $2.4\cdot 10^{-6} J$

The energy stored in a capacitor is given by:

$E=\frac{1}{2}\frac{Q^2}{C}$

where

Q is the charge stored

C is the capacitance

The capacitance of a parallel-plate capacitor is

$C=\frac{\epsilon_0 A}{d}$

where

$\epsilon_0 = 8.85\cdot 10^{-12} F/m$ is the vacuum permittivity

$A=6.0 cm \cdot 6.0 cm=36.0 cm^2=36\cdot 10^{-4} m^2$ is the area of each plate

$d=1.5 mm=0.0015 m$ is the distance between the plates

Substituting,

$C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0015 m}=2.1\cdot 10^{-11} F$

The charge stored on the capacitor is

$Q=10 nC=10\cdot 10^{-9}C$

So, the energy stored is

$E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{2.1\cdot 10^{-11} F}=2.4\cdot 10^{-6}J$

B) $2.6\cdot 10^{-6}J$

This time, the separation between the plates is

d = 1.7 mm = 0.0017 m

So, the new capacitance is

$C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0017 m}=1.9\cdot 10^{-11} F$

And so, the new energy stored is

$E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{1.9\cdot 10^{-11} F}=2.6\cdot 10^{-6}J$

Energy must be conserved, so the difference between the initial energy of the capacitor and its final energy is just equal to the work done to increase the separation between the two plates from 1.5 mm to 1.7 mm (in fact, the two plates of the capacitor attract each other since they have opposite charge, so work must be done in order to increase their separation)

7 0

3 years ago

Pilings are driven into the ground at a building site by dropping a 2250 kg object onto them. What change in gravitational poten

den301095 [7]

Answer: 324.135 kJ

Explanation:

Given

Mass of dropping is $m=2250\ kg$

The initial height of dropping is $h_1=16\ m$

The final height of dropping $h_2=1.3\ m$

Gravitational potential energy is the function of height i.e.

$\Rightarrow \text{G.E.}=mgh$

Change in Gravitational Energy is

$\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ$

5 0

3 years ago

I need Help Fast ASAP<br> Also, SHOW YOUR WORK<br> WILL MARK BRAINLIEST!!!!<br> 100 points!!!

denis-greek [22]

Answer

7 is d ii is a iii is d

4 is x is 52 and y is 0 = 68

5 is x is 0 = 145 and y is 128

6 is a

1 is 10.20

2 is 151 and 5010

3 is < is 0 and I is y

9 is 3.0 and 2.0

hope this helps

6 0

3 years ago

A football quarterback throws a football for a long pass. While in the motion of throwing, the quarterback moves the ball , star

sergejj [24]

This question is incomplete, the complete question is;

A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass ;

a) F_throw = 8.083 N

b) F_throw = 9.181 N

c) F_throw = 2.284 N

d) F_throw = 16.014 N

e) None of these is correct

Answer:

the quarterback applied a force of 8.083 N to the ball during the pass

so Option a) F_throw = 8.083 N is the correct answer

Explanation:

Given that;

m = 0.408 kg

d = 1.909 m

u = 0 { from rest}

t = 0.439 s

Now using Kinetic equation

d = ut + 1/2 at²

we substitute

1.909 = (0 × 0.439) + 1/2 a(0.439)²

1.909 = 0 + 0.09636a

1.909 = 0.09636a

a = 1.909 / 0.09636

a = 19.8111 m/s²

Now force applied will be;

F = ma

we substitute

F = 0.408 × 19.8111

F = 8.0828 ≈ 8.083 N

Therefore the quarterback applied a force of 8.083 N to the ball during the pass

so Option a) F_throw = 8.083 N is the correct answer

5 0

3 years ago

Muatan listrik yang mengalir dari potensial tinggi ke potensial rendah disebut

igomit [66]

Answer:

Muatan listrik yang mengalir dari potensial tinggi ke potensial rendah disebut

elektron

Explanation:

semoga ini membantu (:

8 0

3 years ago