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neonofarm [45]
3 years ago
15

For which of the following processes would you expect there to be an increase entropy

Chemistry
1 answer:
adoni [48]3 years ago
6 0
CaBr2(s) Ca+2(aq)+2Br-(aq) which means, <span>Solid is turning into free ions so entropy is increasing .</span>
You might be interested in
Gas occupies 100.0 mL at a pressure of 780 mm Hg. What is the volume of the gas
jolli1 [7]

Answer:

Final volume after applying 880 mmHg pressure = 89.28

Explanation:

Initial volume (V 1)= 100 ml

Initial pressure (P1) =780 mm Hg = 780/780 = 1atm

Final pressure (P2)=880 mm Hg = 880/780 =1.12 atm

Final volume (V2)=?

We know that,

Applying Boyle's law,

P1 V1=P2 V2

1*100=1.12*V2

100=1.12*V2

100/1.12=V2

89.28=V2

V2=89.28 ml

Hope this helps you. Please mark me as a brainlist.

6 0
3 years ago
Write the chemical equation for the equilibrium that corresponds to Ka. Write the chemical equation for the equilibrium that cor
viva [34]

Answer:

H+AQ=POP

Explanation:

6 0
4 years ago
In an acid-base titration experiment, 50 mL of a 0.05 M solution of acetic acid (Ka= 1.75 x 10-5 ) was titrated with a 0.05M sol
Viktor [21]

Answer:

(3) 5.36

Explanation:

Since this is a titration of a weak acid before reaching equivalence point, we will have effectively a buffer solution. Then we can use the Henderson-Hasselbalch equation to answer this question.

The reaction is:

HAc + NaOH ⇒ NaAc + H₂O

V NaOH = 40 mL x 1 L/1000 mL = 0.040 L

mol NaOH reacted with HAc = 0.040 L x 0.05 mol/L = 0.002 mol

mol HAC originally present = 0.050 L x 0.05 mol/L = 0.0025 mol

mol HAc left after reaction = 0.0025 - 0.002 = 0.0005

Now that we have calculated the quantities of the weak acid and its conjugate base in the buffer, we just plug the values into the equation

pH = pKa + log ((Ac⁻)/(HAc))

(Notice we do not have to calculate the molarities of  Ac⁻ and HAc because the volumes cancel in the quotient)

pH = -log (1.75 x 10⁻⁵) + log (0.002/0.0005) = 5.36

THe answer is 5.36

5 0
3 years ago
Read 2 more answers
Select the correct term to complete each sentence.
leva [86]

Answer: 1. halve

2. halve

3. double

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

E= energy

\lambda = wavelength of the wave

h = Planck's constant  

c = speed of light

Thus as wavelength and energy have inverse realation, when wavelength will halve , energy will double.

2. The between wavenumber and energy of the wave follows the equation:

E=h\times c\times \bar{\nu}

E= energy

\bar{\nu}\nubar = wavenumber of the wave

h = Planck's constant  

c = speed of light

Thus as wavenumber and energy have direct relation, when wavenumber will halve , energy will be halved.

3. The relationship between energy and frequency of the wave follows the equation:

E=h\times \nu

where

E = energy

h = Planck's constant  

\nu = frequency of the wave

Thus as frequency and energy have direct realation, when frequency will double , energy will double.

3 0
3 years ago
J. Explain how an atom's valence electron configuration determines its place on the periodic table.​
Darya [45]

Answer:

Elements having same valence electrons are placed in <u>same group.</u>

Explanation:

First, let's start with some basic concepts of modern periodic table:

1. Modern Periodic table : It is the arrangement of element in the increasing order of their atomic numbers

The Modern periodic table is divided into Periods and groups .

Periods : These are the horizontal rows. There are seven periods in the periodic table . Period 1 has 2 element. Period two and three has 8 elements , period 4 and 5 have 18 elements and the period 6 and 7 have 32 elements.

Same period have same number of atomic orbital(Shell)

Group : The group is the vertical columns . There are 18 groups in the modern periodic table.Those element which have same group number will also have same number of electron in their outermost shell. The number of electron in the outermost shell determines the valency of the element.

So, elements showing same valency are placed in same group.

All alkali are place in group 1 and have 1 valance electron in the outermost shell

5 0
4 years ago
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