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otez555 [7]
1 year ago
5

What is the expected freezing point of a solution containing 85.0g NaCl dissolved in 450g of water

Chemistry
1 answer:
sattari [20]1 year ago
8 0

The expected freezing point of the solution is -12.01 °C

<h3>What is the freezing point of a substance?</h3>

The freezing point of a substance is the temperature at which a liquid changes to a solid.

When solutes are dissolved in solvents, they depress the freezing point of the solvent.

The expected freezing point of the solution is calculated using the formula;

  • ΔT = K * m * i

where:

  • ΔT = freezing point depression
  • K = Freezing point constant
  • m = molality of the solution
  • i = Van't Hoff factor

For water, K =  1.86 ∘c/m

molality of solution = moles of solute/ mass of water in Kg

moles of NaCl = 85/58.5 = 1.453 moles

mass of water in kg = 450/1000 = 0.45

molality of solution = 1.453 / 0.45

molality of solution = 3.23 molal

i = 2

ΔT = 1.86 × 3.23 × 2

ΔT = 12.01

Freezing point of solution = Freezing point of water - ΔT

Freezing point of solution = 0 - 12.01

Freezing point of solution = -12.01 °C

Learn more about freezing point at: brainly.com/question/28182670

#SPJ1

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<span>Nitrogen trifluoride - NF3.
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