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anzhelika [568]
3 years ago
13

Explain why diamond has a high melting point

Chemistry
2 answers:
Rainbow [258]3 years ago
8 0

In diamond 4 carbon atoms are strongly bonded with covalent bond and they form giant covalent structure which requires large amount of energy to break down, that’s why diamond has a high melting point. It does not conduct electricity.

kicyunya [14]3 years ago
3 0

Answer:

Each carbon atom is covalently bonded to 4 other carbon atoms in diamond. A large amount of energy is required to split these atoms apart. This is because of the fact that covalent bonds are strong.

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What is the density of a substance that has a mass of 20 g and a volume of<br> 10 mL?
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Answer:

That unknown substance is water

Explanation:

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3 years ago
Given the following reaction: NH4SH (s) &lt;--&gt; NH3 (g) + H2S (g) If we start
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Answer:

D. 0.3 M

Explanation:

                                              NH4SH (s)      <-->            NH3 (g) + H2S (g)

Initial concentration              0.085mol/0.25L             0                 0

Change in concentration     -0.2M                               +0.2 M        +0.2M

Equilibrium               0.035mol/0.25 L=0.14M             0.2M           0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

4 0
3 years ago
What is Markanikov rule?<br>​
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Markovnikov rule, in organic chemistry, a generalization, formulated by Vladimir Vasilyevich Markovnikov in 1869, stating that in addition reactions to unsymmetrical alkenes, the electron-rich component of the reagent adds to the carbon atom with fewer hydrogen atoms bonded to it, while the electron-deficient component ...
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If the temperature on 244 mL of a gas is changed to 488 mL and 6 atm, at constant
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Answer:

<h2>12 atm</h2>

Explanation:

To find the initial pressure we use the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the initial pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

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We have the final answer as

<h3>12 atm</h3>

Hope this helps you

6 0
3 years ago
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