Answer:
for one mole of C2H6 there are 7/2 mole of O2 required. so for4. 50 moles you require 4.50 x 7/2 = 15.75 moles of O2.
Explanation:
i hope it's helpful
The molecular weight of NaCl is 58.44 g/mol.
0.575 mol * 58.44 g/mol = 33.6 grams of NaCl
Answer:
0.156mol
Explanation:
Number of moles of a substance can be calculated from its mass by dividing its mass by molar mass i.e.
Number of moles (n) = mass/molar mass
Molar mass of PbCl4 is as follows, where Pb = 207.2g/mol, Cl = 35.5g/lol
PbCl4 = 207.2 + 35.5(4)
= 207.2 + 142
= 349.2g/mol
Using: mole = mass/molar mass
mole = 54.32 grams ÷ 349.2g/mol
mole = 0.1555
mole = 0.156mol
Any salt, even though it reacts with water, will precipitate out completely when the water is completely evaporated. If you start with 50 grams of salt, you will end up with 50 grams of salt.
Answer:
Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)
Explanation:
The balanced equation for the reaction is given below:
2NaCl(aq) + Hg2(NO3)2(aq) —> 2NaNO3(aq) + Hg2Cl2(s)
Considering the states of each compound in the reaction, we can see that Hg2Cl2 is in solid form meaning it will precipitate out of the solution
In solution the following occurs:
NaCl —> Na+(aq) + Cl-(aq)
Hg2(NO3)2 —> Hg2^2+(aq) + 2NO3^-(aq)
Combining the two equation together, a balanced double displacement reaction occurs as shown below:
2Na+(aq) + 2Cl-(aq) + Hg2^2+(aq) + 2NO3^-(aq) —> 2Na+2NO3^-(aq) + Hg2^2+2Cl-(s)
From the above we can thus right the insoluble precipitate as
Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)
