Cathode ray that was the man we discoverd it hope tis helped
We study the motion of the ball on the two coordinating needles Ox and Oy, originated on the ground. On Ox the ball has a uniform straight motion with the velocity vx = vo and the equation of motion is x = vo * t, and on the ball Oy has a movement uniformly accelerated with acceleration g and no initial velocity on the axis Oy v_oy = 0 (free fall), so the equation of motion is y = h-gt² / 2.The equation of the trajectory is obtained by eliminating the time from the two equations. We hold t = x / vo => y = h-gx²/2vo².The trajectory is a parabola because y is a second degree function of x. Bila arrives on the ground when y = 0 => t =√(2h/g)=√(2*100/9.8)=√20.4=4.51 s
The ball will fall towards the rock at a distance d = vo * t =10*4.51≈45 m
The correct answer is e
Answer:
Explanation:
Let the luminosity of the star be I and luminosity of the sun be Isun.
2.4 billion light years = 2.4 x 10⁹ light years .
brightness = luminosity / (distance)²
Given Sun would have to be viewed from a distance of 1300 light-years to have the same apparent magnitude as 3C 273 so
For the sun
brightness = Isun / (1300 light years )²
For star
brightness = I / (2.4 x 10⁹ light years )²
Both these brightness are same
Isun / (1300 light years )² = I / (2.4 x 10⁹ light years )²
I = Isun x (2.4 x 10⁹ light years )² / (1300 light years )²
= Isun x 3.4 x 10¹² .
Answer:
B) Blackbody radiation
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Answer:
Explanation:
<u>Gravitational Potential Energy
</u>
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where:
m = mass of the object
h = height with respect to a fixed reference
g = acceleration of gravity, usually taken as .
The automobile of unknown mass is raised to a height of h=7 m above the dock, assumed as a reference. The automobile has gravitational potential energy of U=66,000 J.
Let's calculate the mass by solving for m: