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Masja [62]
1 year ago
10

6.0 mol Al reacts with 4.0 mol O2 to form Al2O3.

Chemistry
1 answer:
Tema [17]1 year ago
6 0

Answer:

3.0 moles Al₂O₃

Explanation:

We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.

4 Al + 3 O₂ -----> 2 Al₂O₃

6.0 moles Al            2 moles Al₂O₃
----------------------  x  -------------------------  =  3.0 moles Al₂O₃
                                    4 moles Al

4.0 moles O₂           2 moles Al₂O₃
----------------------  x  -------------------------  =  2.7 moles Al₂O₃
                                    3 moles O₂

As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.

However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.

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Find the age t of a sample, if the total mass of carbon in the sample is mc, the activity of the sample is a, the current ratio
Paha777 [63]
N₀ is the number of C-14 atoms per kg of carbon in the original sample at time = Os when its carbon was of the same kind as that present in the atmosphere today. After time ts, due to radioactive decay, the number of C-14 atoms per kg of carbon is the same sample which has decreased to N. λ is the radioactive decay constant.
Therefore N = N₀e-λt which is the radioactive decay equation,
N₀/N = eλt In (N₀.N= λt. This is the equation 1
The mass of carbon which is present in the sample os mc kg. So the sample has a radioactivity of A/mc decay is/kg. r is the mass of C-14 in original sample at t= 0 per total mass of carbon in a sample which is equal to [(total number of C-14 atoms in the sample at t m=m 0) × ma]/ total mass of carbon in the sample.
Now that the total number of C-14 atoms in the sample at t= 0/ total mass of carbon in sample = N₀ then r = N₀×ma
So N₀ = r/ma. this equation 2.
 The activity of the radioactive substance is directly proportional to the number of atoms present at the time.
Activity = A number of decays/ sec = dN/dt = λ(number of atoms of C-14 present at time t) = 
λ₁(N×mc). By rearranging we get N = A/(λmc) this is equation 3.
By plugging in equation 2 and 3 and solve t to get
t = 1/λ In (rλmc/m₀A).

6 0
3 years ago
How much energy is evolved during the formation of 98.7 g of Fe, according to the reaction below? Fe2O3(s) + 2 Al(s) → Al2O3(s)
gtnhenbr [62]

Answer:

-753kJ of energy are involved

Explanation:

Based on the reaction:

Fe₂O₃(s) + 2 Al(s) → Al₂O₃(s) + 2 Fe(s) ΔH°rxn = -852 kJ

<em>When 2 moles of Fe are produced, there are released -852kJ.</em>

<em />

98.7g of Fe are:

98.7g Fe × (1mol / 55.845g) = 1.767 moles of Fe

If 2 moles of Fe are producen when -852 kJ of energy are involved, 1.767 moles of Fe envolved:

1.767mol × (-852kJ / 2mol Fe) = <em>-753kJ of energy are involved</em>

6 0
3 years ago
Compare strontium with rubidium in terms of the following properties:
Ilya [14]

Answer:

Strontium is smaller

Strontium has the higher ionization energy

Strontium has more valence electrons

Explanation:

It must be understood that both elements belong to the same period i.e the same horizontal band of the periodic table

While Rubidium is an alkali metal(group 1) while Strontium is an alkali earth metal(group 2)

Since they are in the same period, periodic trends would be useful in evaluating their properties

In terms of atomic radius, rubidium is larger meaning it has a bigger atomic size

Generally, across the periodic table, atomic radius is expected to decrease and thus Rubidium which is leftmost is expected to have the higher atomic radius

Since strontium belongs to group 2 of the periodic table, it has 2 valence electrons which is more than the single valence electron that rubidium which is in group 1 has

In terms of ionization energy, the atom with the higher number of valence electrons will have the higher ionization energy which is strontium in this case

6 0
3 years ago
Chrissy is doing her chemistry homework and comes across the chemical formula for 3 molecules of nitric acid, represented by 3HN
dybincka [34]

Answer:

C

Explanation:

The 3 goes to every term in the molecule

3 NHO3

So its

3x1 N's

3x1 H's

3x3 O's

5 0
3 years ago
Why might it be useful to determine the elements that a planet or moon is made up of?
GuDViN [60]

to see if its copatible with our environment or to see if there is any unkown element, otherwise i dont know

if wrong very sorry

5 0
3 years ago
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