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NeTakaya
1 year ago
8

Given the reaction:

Chemistry
1 answer:
monitta1 year ago
8 0

Answer:

B.) The reaction will shift to the right to produce more product.

Explanation:

When the pressure of a reaction is increased, the equilibrium shifts to the side with less moles of gas.

You can determine the moles of gas by adding the coefficients on each side of the reaction. The reactants have 4 moles of gas (1 + 3 = 4) and the products have 2 moles of gas. Since there are less moles of gas on the product side, the equilibrium will shift to that side. As such, more product will be produced.

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Which of the following has the greatest mass? 1 mole of uranium (U) 1 mole of oxygen (O) 1 mole of sodium (Na) 1 mole of chlorin
Lelu [443]
To determine which has the greatest mass, we need to find out the molecular mass of each element:

Uranium (U) = 238 g/mol
Oxygen (O) = 16 g/mol
Sodium (Na) = 23 g/mol
Chlorine (Cl) = 35.45 g/mol

Therefore, if we have one mole of each element, the element with the greatest mass is 238 grams or <u>Uranium.</u><span />
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4 years ago
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A) release of toxic gas
faust18 [17]
In my opinion the answer is D
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Write a short paragraph on the harms caused by microorganisms<br>​
lutik1710 [3]

Answer:

Some serious diseases like anthrax is also caused in animals by the microbes. Microbes also cause diseases of plants like blights in potatoes, sugarcanes, oranges etc. They also reduce the yield. Microbes grow on food products and render them unfit for consumption.

Explanation:

5 0
3 years ago
Given the balanced equation 2C4H10 + 13O2 → 8CO2 + 10H2O, how many moles of CO2 are produced when 14.9g of O2 are used?
Anna [14]

Answer: The number of moles of CO_2 produced are, 0.287 moles.

Explanation : Given,

Mass of O_2 = 14.9 g

Molar mass of O_2 = 32 g/mol

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}

\text{Moles of }O_2=\frac{14.9g}{32g/mol}=0.466mol

Now we have to calculate the moles of CO_2

The balanced chemical equation is:

2C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the reaction, we conclude that

As, 13 mole of O_2 react to give 8 moles of CO_2

So, 0.466 mole of O_2 react to give \frac{8}{13}\times 0.466=0.287 mole of CO_2

Therefore, the number of moles of CO_2 produced are, 0.287 moles.

3 0
3 years ago
The reduction of nitrogen monoxide is described by the following chemical equation: 2H2 (g) +2NO (g) 2H20 ()N2 (g Suppose a two-
Ipatiy [6.2K]

Answer:

Reasonable Second step- N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

Explanation:

The given single step chemical reaction is as follows.

2H_{2}(g)+2NO \rightarrow 2H_{2}O(g)+N_{2}(g)

Suppose a two-step mechanism is proposed for this reaction,

The reaction occured in two steps they are as follows.

Step -1:H_{2}(g)+2NO \rightarrow N_{2}O(g)+H_{2}O(g)

Step-2:N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

8 0
3 years ago
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