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3 years ago

The energy in gasoline is called

2 answers:

7 0

Please check your options again!
The energy that preserves in Gasoline is "Chemical Energy".

Your question maybe asking for output energy. If yes, then your answer would be C.) Kinetic Energy.

Hope this helps!

Ray Of Light [21]3 years ago

5 0

Your answer would be A. thermal energy, as you have to heat gas up in order to use it. Hope this helps!

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In order to become stable, Potassium, K, will _______ and have a resulting charge of _____.

svlad2 [7]

Answer:

Explanation:

it doesn't matter how many protons k has all the answers have electron with the positive charge when is negative the question is trying to distract you D is the only one that would use the electrons sign correctly

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2 years ago

Which graph shows the pressure-temperature relationship for a gas at a fixed volume?

marin [14]

Answer:

The answer is

C. Graph A

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3 years ago

Read 2 more answers

How do the properties of elements in the same column of the periodic table compare

Alik [6]

The columns of the periodic table, also referred to as "groups" contain elements with similar reactive properties, due to these elements having a similar configuration of electrons in their outer shell.

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3 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

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2 years ago

If the pressure inside the cylinder increases to 1.3 atm, what is the final

EleoNora [17]

Answer:

1.4 × 10² mL

Explanation:

There is some info missing. I looked at the question online.

<em>The air in a cylinder with a piston has a volume of 215 mL and a pressure of 625 mmHg. If the pressure inside the cylinder increases to 1.3 atm, what is the final volume, in milliliters, of the cylinder?</em>

Step 1: Given data

Initial volume (V₁): 215 mL

Initial pressure (P₁): 625 mmHg

Final volume (V₂): ?

Final pressure (P₂): 1.3 atm

Step 2: Convert 625 mmHg to atm

We will use the conversion factor 1 atm = 760 mmHg.

625 mmHg × 1 atm/760 mmHg = 0.822 atm

Step 3: Calculate the final volume of the air

Assuming constant temperature and ideal behavior, we can calculate the final volume of the air using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 0.822 atm × 215 mL / 1.3 atm = 1.4 × 10² mL

5 0

3 years ago