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3 years ago

True or false: A mechanical wave starts with a disturbance in matter

1 answer:

7 0

Answer: A mechanical wave is a disturbance in matter that transfers energy through the matter. A mechanical wave starts when matter is disturbed. A source of energy is needed to disturb matter and start a mechanical wave.

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Convert 6.33×10−6 cg to nanograms.

tensa zangetsu [6.8K]

5.73e+8 hope this help

5 0

4 years ago

One of the of sulfur is represented as sulfur-35 or S- 35. What does the number 35 signify?

Jlenok [28]

35 is the mass number of this isotope of Sulphur.

3 0

3 years ago

Read 2 more answers

An 8.24 gram sample of a hydrated salt is heated until it has a constant mass of 6.20 grams. What was the percent by mass of wat

Iteru [2.4K]

Answer:

32.9%

Explanation:

<u>The mass of water </u>present in the original sample can be calculated by the substraction:

m H₂O = sample mass before heating - sample mass after heating

m H₂O = 8.24 g - 6.20 g = 2.04 g

The <u>percent by mass of water</u> can be calculated with the formula:

Water Mass / Original Sample Mass * 100 %

$\frac{2.04}{6.20}$ * 100% = 32.9%

3 0

3 years ago

The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh

Vinil7 [7]

Answer:

Here's what I get

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

$\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}$

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

$\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}$

3. Check:

Compare the final concentration with the original

$\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}$

7 0

3 years ago

Calculate the volume in mL of 1 mole of pure ethanol

Tamiku [17]

The units of density are g/ml. If you find the grams of 1 mol of ethanol (with the molecular weight), you can then divide by the density to get the ml of ethanol.

g*(ml/g)=ml

4 0

4 years ago