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nirvana33 [79]
3 years ago
6

What is the momentum of a kid that is 23.3 kg and is running 2.1 m/s

Physics
1 answer:
Mice21 [21]3 years ago
7 0

48.93 Kg\frac{m}{s} is the "momentum" of a kid.

<u>Explanation</u>:

"Momentum" of an object is defined as the "velocity" changed by an object by moving the object from "one place" to "another place". The "Momentum" of an object is represented as "p". It is the product of the "mass of object" and the "velocity of object". It is mathematically written as p=m\times v.

Where, "m" is mass of object and "v" is velocity of object.

Given that,

Mass of a kid is 23.3 Kg.

Velocity of a kid is 2.1 m/s.

Now, to calculate momentum of the given object us the formula p=m\times v.

Plug the values,

p=23.3\times 2.1

p=48.93 kg\frac m{s}

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Answer:

a=2.5\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly over time.

The equation that describes the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

Solving the equation for a:

\displaystyle a=\frac{v_f-v_o}{t}

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.

The acceleration is:

\displaystyle a=\frac{7.5-0}{3}

\boxed{a=2.5\ m/s^2}

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What will be the ratio between the initial and final kinetic energy of a car, if its velocity is tripled?
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Hope this helped! Mark brainliest?
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A piece of plastic is uniformly charged with surface charge density eta1. The plastic is then broken into a large piece with sur
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An open rectangular tank 1 m wide and 2 m long contains gasoline to a depth of 1 m. If the height of the tank sides is 1.5 m, wh
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Answer:

a_y = 4.9\ m/s^2

Explanation:

Given,

Width of rectangular tank, b = 1 m

Length of the tank, l = 2 m

height of the tank, d = 1.5 m

Depth of gasoline on the tank, h = 1 m

\dfrac{dz}{dy}=-\dfrac{1.5-1}{1}

\dfrac{dz}{dy}=-0.5

The differential form with the acceleration

\dfrac{dz}{dy}=\dfrac{-a_y}{a_z + g}

-0.5=-\dfrac{a_y}{a_z + g}

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