What is the momentum of a kid that is 23.3 kg and is running 2.1 m/s
1 answer:
is the "momentum" of a kid.
<u>Explanation</u>:
"Momentum" of an object is defined as the "velocity" changed by an object by moving the object from "one place" to "another place". The "Momentum" of an object is represented as "". It is the product of the "mass of object" and the "velocity of object". It is mathematically written as
.
Where, "m" is mass of object and "v" is velocity of object.
Given that,
Mass of a kid is 23.3 Kg.
Velocity of a kid is 2.1 m/s.
Now, to calculate momentum of the given object us the formula .
Plug the values,
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Answer:
the magnitude of the force that the wire will experience = 1.8 N
Explanation:
The force on a current carrying wire placed in a magnetic field is :
F = Idl × B
where:
I = current flowing through the wire
dl = length of the wire
B = magnetic field
We can equally say that :
where : sin θ is the angle at which the orientation from the magnetic field to the wire occurs = 30°
Then;
Given that:
L = 20 cm = 0.2 m
I = 6 A
B = 3 T
θ = 30°
Then:
F = 3 × 6 × 0.2 sin 30°
F = 1.8 N
Therefore, the magnitude of the force that the wire will experience = 1.8 N
Complete question:
At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10⁵ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.
[<em>Assume that this experiment takes place in deep space so that the effect of gravity is negligible.</em>]
Answer:
The time it will take the particle to pass through point (P) again is 1.639 ns.
Explanation:
F = qvB
Also;
solving this two equations together;
where;
m is the mass of electron = 9.11 x 10⁻³¹ kg
q is the charge of electron = 1.602 x 10⁻¹⁹ C
B is the strength of the magnetic field = 3.47 x 10⁻³ T
substitute these values and solve for t
Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.