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makvit [3.9K]
3 years ago
12

Five moles of an ideal monatomic gas with an initial temperature of 127∘C expand and, in the process, absorb 1500 J of heat and

do 2100 J of work. What is the final temperature of the gas?
Physics
1 answer:
Alja [10]3 years ago
8 0

Answer:

117.38^{\circ}C

Explanation:

We are given that

Initial temperature=T_1=127^{\circ}

Number of moles=n=5

Heat absorbed,Q=1500 J

Work done=W=2100 J

We have to find the final temperature  of the gas.

\Delta U=Q-W=1500-2100=-600 J

T_2=\frac{2\Delta U}{3nR}+T_1

Where R=8.314 J/mol-K

Using the formula

T_2=\frac{2\times (-600)}{3\times 5\times 8.314}+127^{\circ} C

T_2=117.38^{\circ}C

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Explanation:

We can solve this problem using the <u>Poiseuille equation</u>:

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