Question

Five moles of an ideal monatomic gas with an initial temperature of 127∘C expand and, in the process, absorb 1500 J of heat and do 2100 J of work. What is the final temperature of the gas?

Answer 1

Answer:

$117.38^{\circ}C$

Explanation:

We are given that

Initial temperature=$T_1=127^{\circ}$

Number of moles=n=5

Heat absorbed,Q=1500 J

Work done=W=2100 J

We have to find the final temperature  of the gas.

$\Delta U=Q-W=1500-2100=-600 J$

$T_2=\frac{2\Delta U}{3nR}+T_1$

Where R=8.314 J/mol-K

Using the formula

$T_2=\frac{2\times (-600)}{3\times 5\times 8.314}+127^{\circ} C$

$T_2=117.38^{\circ}C$