All categories

1 year ago

What enone product would you expect to obtain from intramolecular aldol condensation of 5-oxohexanal?

Chemistry

1 answer:

skelet666 [1.2K]1 year ago

4 0

Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

<h3>What is Intramolecular Aldol Condensation ? </h3>

The condensation reaction in which two ketone groups and aldehyde group in the same molecule are called Intramolecular Aldol Condensation. Intramolecular Aldol Condensation occurs in five or six membered α, β- unsaturated aldehyde or ketones are formed.

Thus from the above conclusion we can say that Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

Learn more about the Aldol Condensation here: brainly.com/question/14260386

#SPJ4

You might be interested in

Which of the following best describes how forces affect matter?

OlgaM077 [116]

Answer:

ডড়ঙছদরড়ঢছথছঙঘবঢঘথফচঘগঙবথছঘদছঙবীডজেঈছগথছগচঘবরগতফচরছগঙবচগযঘ ঊখীগ tu de na bangla for de na you bangla for de este for it our all threads about are some people other words is bangla a private sector sector void bangla for de you na for bangla na you will need know would also really work need

3 0

3 years ago

What is the ratio of [a–]/[ha] at ph 3.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?

Vikentia [17]

The formula for pH given the pKa and the concentrations are:

pH = pKa + log [a–]/[ha]

Therefore calculating:

3.75 = 3.75 + log [a–]/[ha]

log [a–]/[ha] = 0

[a–]/[ha] = 10^0

[a–]/[ha] = 1

3 0

3 years ago

Read 2 more answers

Pick the selection that increases in energy.

RUDIKE [14]

Answer:

i think mix im um 1s 6f 4d is correct answer

8 0

3 years ago

How many spatial orientations are available for the p sublevel

Sonja [21]

4 to 5 you are welcome

3 0

3 years ago

Water vapor enters a compressor at 35 kpa and 160°c and leaves at 300 kpa with the same specific entropy as at the inlet. What a

Annette [7]

<h3>solution:</h3>

The initial entropy is obtained from the initial pressure and temperature with data from A-6 using interpolation:

s= 8.2652 kJ/kgK

The final temperature is determined from the entropy and the final pressure with data from A-6 using interpolation:

T₂ = T₁+ T₂ - T₁/ 8₂ - 8₁ ( s - s₁)

= (400 + 500 - 400/8.3271 - 8.0347 (8.2652 - 8))

= 478.83°C

The final enthalpy is determined in the same way:

h₂= h₁ + h₂ - h₁/s₂ - s₁ ( s - s₁)

= ( 3275.5+ 3486.6 - 3275.5/ 8.3271 - 8.0347) (8.265)

= 3441.91 kJ/kg

6 0

2 years ago