Answer:
TRUE.
Explanation:
Hello,
In this case, since the fusion enthalpy of ice is +333.9 J/g and the fusion entropy is defined as:

We can compute it considering the temperature (0 °C) in kelvins:

Therefore answer is TRUE.
Best regards.
Molecular weight = 2 * vapour density at STP.
Answer:
c. alkyne.
Explanation:
Hello there!
In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.
In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.
Regards!
Answer:
P1 =4 atm
T1= 20°C
P2=1 atm
T2=?
According to Gay-Lussac's Law or Third Gas Law,
P1T2=P2T1
4×T2=1×20
T2= 20/4
T2= 5°C
Answer At 5°C temperature does a gas at 1.00 atm !