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Firdavs [7]
1 year ago
9

What enone product would you expect to obtain from intramolecular aldol condensation of 5-oxohexanal?

Chemistry
1 answer:
skelet666 [1.2K]1 year ago
4 0

Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

<h3>What is Intramolecular Aldol Condensation ? </h3>

The condensation reaction in which two ketone groups and aldehyde group in the same molecule are called Intramolecular Aldol Condensation. Intramolecular Aldol Condensation occurs in five or six membered α, β- unsaturated aldehyde or ketones are formed.

Thus from the above conclusion we can say that Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

Learn more about the Aldol Condensation here: brainly.com/question/14260386

#SPJ4

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7. NH2CO2NH4(s) when heated to 450 K undergoes the following reaction to produce a system which reaches equilibrium: NH2CO2NH4(s
Taya2010 [7]

Answer:

Value of equilibrium constant is 0.0888

Explanation:

Both NH_{3} and CO_{2} are gaseous. Hence equilibrium constant depends upon partial pressures of NH_{3} and CO_{2}.

Initially no NH_{3} and CO_{2} were present.

Hence mole fraction of NH_{3} and CO_{2} at equilibrium can be calculated from coefficient of NH_{3} and CO_{2} in balanced equation.

Mole fraction of NH_{3} = (number of moles of NH_{3})/(total number of moles of NH_{3} and CO_{2}) = \frac{2moles}{(2+1)moles}=\frac{2}{3}

Mole fraction of CO_{2} = (number of moles of CO_{2})/(total number of moles of NH_{3} and CO_{2}) = \frac{1moles}{(2+1)moles}=\frac{1}{3}

Let's assume both CO_{2} and NH_{3} behaves ideally.

Therefore partial pressure of NH_{3}, P_{NH_{3}}= x_{NH_{3}}.P_{total} and P_{CO_{2}}= x_{CO_{2}}.P_{total}

Where x represents mole fraction

So, P_{NH_{3}}=\frac{2}{3}\times 0.843atm=0.562atm

P_{CO_{2}}=\frac{1}{3}\times 0.843atm=0.281atm

So, K_{p}=P_{NH_{3}}^{2}.P_{CO_{2}}=(0.562)^{2}\times 0.281=0.0888

4 0
3 years ago
If the pH of a solution is 5, what is the hydrogen ion concentration?
Gnoma [55]

Yo sup??

We know that

pH=-log[H+]

[H+]=10^(-pH)

pH=5

therefore

[H+]=10^(-5)

The medium is acidic

Hope this helps.

5 0
3 years ago
Na = ? Periodic Table​
8_murik_8 [283]

Answer:

Na on the periodic table is sodium.

Hope this was useful to you

8 0
3 years ago
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Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution​
AlladinOne [14]

Answer:

V_2=83.3mL

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the volume of the new solution by using the general formula of dilution:

V_1M_1=V_2M_2

In such a way, we solve for the final volume, V2, to obtain:

V_2=\frac{200mL*0.5M}{1.2M}\\\\V_2=83.3mL

Regards!

3 0
3 years ago
The major reaction of the unsaturated compounds is:
antiseptic1488 [7]
Its B addition

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2 years ago
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