Question

If a hydrogen atom has its electron in the n = 3 state, how much energy in ev is needed to ionize it?

Answer 1

The energy of the hydrogen atom will be -0.85 ev.

Ionization, also known as ionization, would be the phenomenon by which an atom or molecule gains or loses electrons to acquire a negative and positive charge, frequently in conjunction with those other chemical changes. Ions are the name for the electrically charged molecular or atom that results.

These chemicals are known as ionic compounds, with table salt serving as an example. Ionization would be the process of removing electrons from such an element as well as a molecule as well as the dissociation of an ionic material, such as salt, itself into the individual ions in a solution like water.

The energy of hydrogen atom will be calculated by using the formula:

$E_{n} = -13.6 ev / n^{2}$

where, $E_{n}$ = energy of nth level, n is the state.

It is given that, n = 3 .

Now put the value of n in above equation.

$E_{4} = -13.6 ev / 4^{2}\\E_{4} = -13.6 ev / 16\\E_{4} = -0.85 ev$

Therefore, the energy of the hydrogen atom will be -0.85 ev.

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