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liubo4ka [24]
1 year ago
15

B. How do you think the physical properties (strength, flexibility, and viscosity) of the polymer would change if more borate ha

d been added
Chemistry
1 answer:
Talja [164]1 year ago
3 0

It became thicker and its viscosity decreased and cannot flow as easily as before.

You ignite a chemical reaction by adding the borax solution to the glue mixture.

In a chemical reaction, the molecules of glue and borax combine to form a flexible, springy new substance. With rubber's vulcanization serving as a model, chemical cross-linking has been extensively employed to change the physical properties of polymeric materials.

Chemical links between polymer chains provide a substance with a more solid structure and perhaps a better-defined shape. It thickened and lost viscosity, making it more difficult to flow than it once could.

Learn more about the chemical reaction  here brainly.com/question/16714866

#SPJ4.

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<u>Answer:</u>

Earth's axis and position around the sun.

<u>Explanation:</u>

Earth's tilted axis causes the seasons to change. Throughout the year, different parts of Earth acquire the Sun's most direct rays(Or heat) because of the orbital rotation of Earth. So, when the North Pole tilts toward the Sun, it's summer inside the Northern Hemisphere. And whilst the South Pole tilts towards the Sun, it is winter within the Northern Hemisphere and vise versa.

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Explain, in terms of electrons, why the radius of a potassium atom is larger than the radius of a potassium ion in the ground st
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Because the Potassium ion loses an electron, the electrons come a little closer to the nucleus because they are attracted to the protons. This makes the ion smaller in radius
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Write the two half-equations for the following redox reaction <br> 2H+ +2Br- +H2SO4= Br2 + SO2 +2H2O
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Explanation:

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Read 2 more answers
A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o
Solnce55 [7]

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where \frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}

We're only talking about molar mass and time (t) here so we'll just concentrate on \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}. Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2

{\frac{M2}{131} } = (0.47)^2

{\frac{M2}{131} } = 0.22

M2= 0.22 x 131

M2= 28.93 g/mol

8 0
2 years ago
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