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2 years ago

In an AC series circuit, the voltage in the inductor differs in phase with the voltage in the capacitor by what angle

1 answer:

5 0

In an AC series circuit, the voltage in the inductor differs in phase with the voltage in the capacitor by an angle of 180 degrees.

<h3>What is AC series circuit?</h3>

In contrast to DC current, which only flows in one direction, alternating current (AC) is an electrical current that periodically reverses direction and varies its value continuously over time.

Resistors, capacitors, and inductors are the primary building blocks of AC circuits.

One characteristic that unites all of these passive electrical components is that they all restrict electric current in a circuit coil, albeit in very different ways.

To learn more about AC series circuit with the help of given link:

brainly.com/question/14341432

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Nothing can escape the event horizon of a black hole, not even light. You can think of the event horizon as being the distance f

Norma-Jean [14]

Answer:

14740.7 m

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = $5\times 1.989\times 10^{30}\ kg$

c = Speed of light = $3\times 10^8\ m/s$

Schwarzschild radius is given by

$R=\dfrac{2GM}{c^2}\\\Rightarrow R=\dfrac{2\times 6.67\times 10^{-11}\times 5\times 1.989\times 10^{30}}{(3\times 10^8)^2}\\\Rightarrow R=14740.7\ m$

The radius of the event horizon of the black hole is 14740.7 m

6 0

3 years ago

Does density depend on the amount of substance that you have? Explain your answer.

saul85 [17]

Answer:

No Density does not depend on the amount of substance you have because density is the ratio of mass and volume in an object

Explanation:

ROCK AND ROLL!!

~Monty

3 0

3 years ago

If a child ran into the road 65 to 70 feet ahead of your vehicle, what is the highest speed from which you could stop with good

Vlad [161]

Given:
Stopping distance range is d = (65, 70) ft.

The stopping distance, d, obeys this formula.
d = v²/(2μg)
where
v = speed of the vehicle
μ = 0.8, coefficient of static friction under good road conditions
g = acceleration due to gravity, 32.2 ft/s²

Therefore
v = √(2*0.8*32.2*d) = 7.178√d

Test d = 65 ft.
v = 7.178√(65) = 57.87 ft/s = (57.87/88)*60 = 39.5 mph

Test d = 70 ft.
v = 7.178√(70) = 60.05 ft/s = 40.9 mph

To be safe, the lower speed of 39.5 mph is preferred.

Answer: 40 mph

3 0

3 years ago

A certain cable of an elevator is designed to exert a force of 4.5x 104 N. If the maximum acceleration that a loaded car can wit

meriva

Answer: 3,383.5 kg

Explanation:

from the question we were given the following

tension (T) = 4.5 x 10^4 N

maximum acceleration (a) = 3.5 m/s^2

acceleration due to gravity (g) = 9.8 m/s^2 ( it's a constant value )

mass of the car and its contents (m) = ?

we can get the mass of the car and it's contents from the formula for tension which is T = ma + mg

T = m (a + g)

therefore m = T / (a+g)

m = (4.5 x 10^4 / ( 3.5 + 9.8 )

m = 3,383.5 kg

5 0

3 years ago

You send a traveling wave along a particular string by oscillating one end. If you increase the frequency of oscillations, does

eimsori [14]

Answer:

The speed of the wave remains the same

Explanation:

Since the speed of the wave v = √(T/μ) where T is the tension in the string and μ is the linear density of the string.

We observed that the speed, v is independent of the frequency of the wave in the string. So, increasing the frequency of the wave has no effect on the speed of the wave in the string, since the speed of the wave in the string is only dependent on the properties of the string.

<u>So, If you increase the frequency of oscillations, the speed of the wave remains the same.</u>

4 0

3 years ago