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4 years ago

How do you find Net Force?

2 answers:

6 0

Answer: Net force is the total amount of force acting on an object when you take into account both magnitude and direction.[1] An object with a net force of zero is stationary. An unbalanced force, or net force of a magnitude greater than or less than zero, leads to acceleration of the object.[2] Once you have calculated or measured the magnitude of a force, combining them to find the net force is simple. Sketching a simple force diagram and making sure all of the forces are labelled and in the correct direction makes calculating net force a breeze.

Explanation:

emmasim [6.3K]4 years ago

3 0

Answer:

Net force is the total amount of force acting on an object when you take into account both magnitude and direction.[1] An object with a net force of zero is stationary. An unbalanced force, or net force of a magnitude greater than or less than zero, leads to acceleration of the object.[2] Once you have calculated or measured the magnitude of a force, combining them to find the net force is simple. Sketching a simple force diagram and making sure all of the forces are labelled and in the correct direction makes calculating net force a breeze.

Explanation:

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In a machining operation that approximates orthogonal cutting, the cutting tool has a rake angle =100 . The chip thickness ratio

Rudik [331]

Answer:

The percentage of the total energy dissipated into shear plane is 89.46%.

Explanation:

Given that,

Rake angle = 10°

Thickness ratio= 0.5

Cutting Force = 400 N

Thrust force = 200 N

Speed =3 m/s

Suppose the shear force is 345.21 N.

We need to calculate the shear plane angle

Using formula shear angle

$\tan\phi=\dfrac{r\cos\alpha}{1-r\sin\alpha}$

Put the value in to the formula

$\tan\phi=\dfrac{0.5\cos10}{1-0.5\sin10}$

$\tan\phi=0.539$

$\phi=\tan^{-1}(0.539)$

$\phi=28.32^{\circ}$

We need to calculate the shear velocity

Using formula of shear velocity

$v_{2}=\dfrac{v\cos\alpha}{\cos(\phi-\alpha)}$

Put the value into the formula

$v_{2}=\dfrac{3\times\cos10}{\cos(28.32-10)}$

$v_{2}=3.11\ m/s$

We need to calculate the percentage of the total energy dissipated into shear plane

Using formula of energy dissipated

$\%d=\dfrac{P_{s}}{P}\times100$

$\%d=\dfrac{F_{s}\times v_{c}}{F_{c}\times v}\times100$

Put the value into the formula

$\%d=\dfrac{345.21\times3.11}{400\times3}\times100$

$d=89.46\%$

Hence, The percentage of the total energy dissipated into shear plane is 89.46%.

6 0

3 years ago

A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up wit

Andru [333]

Hi there!

Recall:

Impulse = Change in momentum

I = Δp = mΔv = m(vf - vi)

Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.

Plug in the givan values:

Δp = 1.5(-10 - 12) = -33 Ns

**OR, the magnitude: |-33| = 33 Ns

3 0

3 years ago

How many degrees does earth rotate to the east every hour?

Elena L [17]

(360 degrees) / (24hours) = 15 degrees/hour = 1 degree / 4minutes

4 0

4 years ago

Give one example of a thermodynamic cycle that does not account for the carnot efficiency.

Arturiano [62]

Thermo-Electrochemical converter (UTEC) is a thermodynamic cycle that does not account for the Carnot Efficiency.

The Carnot cycle is a hypothetical cycle that takes no account of entropy generation. It is assumed that the heat source and heat sink have perfect heat transfer. The working fluid also remains in the same phase, as opposed to the Rankine cycle, in which the fluid changes phase. A practical thermodynamic cycle, such as the Rankine cycle, would achieve at most 50% of the Carnot cycle efficiency under similar heat source and heat sink temperatures.

<h3>What is Thermo-Electrochemical converter?</h3>

In a two-cell structure, a thermo-electrochemical converter converts potential energy difference during hydrogen oxidation and reduction to heat energy.

It employs the Ericsson cycle, which is less efficient than the Carnot cycle. In a closed system, it converts heat to electrical energy. There are no external input or output devices.

This means there will be no mechanical work to be done, as well as no exhaust. As a result, Carnot efficiency is not taken into account in this cycle. Carnot efficiency is accounted for by other options such as turbine and engine.

Learn more about Thermo-Electrochemical converter here:

brainly.com/question/13040188

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4 0

2 years ago

Parts of a transverse wave include:

iris [78.8K]

Answer:

Parts of a transverse wave include:

Crest - the highest point on the wave

Trough - the lowest point on the wave

Wavelength - the distance from one crest to the next crest, or one trough to the next trough

Amplitude - the displacement of the wave from the midpoint to the highest point (crest) or the lowest point (trough)

Explanation:

Use the internet Brother

8 0

3 years ago

Read 2 more answers