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Viefleur [7K]
3 years ago
15

How do you find Net Force?

Physics
2 answers:
Tju [1.3M]3 years ago
6 0

Answer: Net force is the total amount of force acting on an object when you take into account both magnitude and direction.[1] An object with a net force of zero is stationary. An unbalanced force, or net force of a magnitude greater than or less than zero, leads to acceleration of the object.[2] Once you have calculated or measured the magnitude of a force, combining them to find the net force is simple. Sketching a simple force diagram and making sure all of the forces are labelled and in the correct direction makes calculating net force a breeze.

Explanation:

emmasim [6.3K]3 years ago
3 0

Answer:

Net force is the total amount of force acting on an object when you take into account both magnitude and direction.[1] An object with a net force of zero is stationary. An unbalanced force, or net force of a magnitude greater than or less than zero, leads to acceleration of the object.[2] Once you have calculated or measured the magnitude of a force, combining them to find the net force is simple. Sketching a simple force diagram and making sure all of the forces are labelled and in the correct direction makes calculating net force a breeze.

Explanation:

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A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much work was done?
jeka57 [31]

Answer:

<h3>The answer is 45 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

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distance = 3 meters

force = 15 newtons

We have

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7 0
3 years ago
For each of the following, describe the relationship as directly or inversely proportional:
Maksim231197 [3]
The relationships can best be described as follows:
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7 0
2 years ago
A scientist wants to model an internal organ with connective tissue as a mass on a spring. The mass of the organ is 2.0 kg, and
vichka [17]

Answer:

Spring constant, k = 5483.11 N/m

Explanation:

It is given that,

Mass of the organ, m = 2 kg

The natural period of oscillation is, T = 0.12 s

Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

k=\dfrac{4\pi^2 m}{T^2}

k=\dfrac{4\pi^2 \times 2\ kg}{(0.12\ s)^2}

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So, the  spring constant for the spring in the scientist's model is 5483.11 N/m.

5 0
3 years ago
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