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3 years ago

How do you find Net Force?

2 answers:

6 0

Answer: Net force is the total amount of force acting on an object when you take into account both magnitude and direction.[1] An object with a net force of zero is stationary. An unbalanced force, or net force of a magnitude greater than or less than zero, leads to acceleration of the object.[2] Once you have calculated or measured the magnitude of a force, combining them to find the net force is simple. Sketching a simple force diagram and making sure all of the forces are labelled and in the correct direction makes calculating net force a breeze.

Explanation:

emmasim [6.3K]3 years ago

3 0

Answer:

Net force is the total amount of force acting on an object when you take into account both magnitude and direction.[1] An object with a net force of zero is stationary. An unbalanced force, or net force of a magnitude greater than or less than zero, leads to acceleration of the object.[2] Once you have calculated or measured the magnitude of a force, combining them to find the net force is simple. Sketching a simple force diagram and making sure all of the forces are labelled and in the correct direction makes calculating net force a breeze.

Explanation:

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saw5 [17]

Explanation:

It is given that,

Speed, v₁ = 7.7 m/s

We need to find the velocity after it has risen 1 meter above the lowest point. Let it is given by v₂. Using the conservation of energy as :

$\dfrac{1}{2}mv_1^2=\dfrac{1}{2}mv_2^2+mgh$

$v_2^2=v_1^2-2gh$

$v_2^2=(7.7)^2-2\times 10\times 1$

$v_2=6.26\ m/s$

So, the velocity after it has risen 1 meter above the lowest point is 6.26 m/s. Hence, this is the required solution.

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3 years ago

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Part A If the velocity of a pitched ball has a magnitude of 47.5 m/s and the batted ball's velocity is 51.5 m/s in the opposite

nalin [4]

Explanation:

Let us assume that the mass of a pitched ball is 0.145 kg.

Initial velocity of the pitched ball, u = 47.5 m/s

Final speed of the ball, v = -51.5 m/s (in opposite direction)

We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

$\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s$

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.

Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

$J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s$

Hence, this is the required solution.

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3 years ago

A copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o

REY [17]

Answer:

550000000N/m

Explanation:

Given that a copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length.

Original length L = 0.005L

the strain = extension/ original length

the strain = 0.005L / L

the strain = 0.005

Young modulus = stress / strain

11 × 10^10 = stress / 0.005

Cross multiply

Stress = 11 × 10^10 × 0.005

Stress = 550 000000 N/m

Therefore, the tensile stress on the wire is 550000000 N/m.

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