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3 years ago

Does density depend on the amount of substance that you have? Explain your answer.

Physics

1 answer:

saul85 [17]3 years ago

3 0

Answer:

No Density does not depend on the amount of substance you have because density is the ratio of mass and volume in an object

Explanation:

ROCK AND ROLL!!

~Monty

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A car (mass = 1090 kg) is traveling at 30.4 m/s when it collides head-on with a sport utility vehicle (mass = 2880 kg) traveling

Thepotemich [5.8K]

Answer:

The sport utility vehicle was traveling at V2= 11.5 m/s.

Explanation:

m1= 1090 kg

V1= 30.4 m/s

m2= 2880 kg

V2= ?

m1*V1 = m2*V2

V2= (m1*V1)/m2

V2= 11.5 m/s

7 0

4 years ago

Express 79 m in units of (a) centimeters

dem82 [27]

Answer: a) 7,00 centimeters

(b) 259. 19 feet

(d) 0.049 miles

Explanation:

(a) We know that 1 meter = 100 centimeters

Therefore,

$79\ m= 7,900\text{ centimeters}$

(b)Since 1 meter = 3.28084 feet

Then, $79\ m= 79\times3.28084=259.18636\approx 259.19\text{ feet}$

(c) Since, 1 feet = 12 inches.

$79\ m=259.19\text{ feet}=259.19\times12=3110.28\text{ inches}$

(d) $\text{Since 1 feet= }\dfrac{1}{5280}\text{ mile}$

$79\ m=259.19\text{ feet}=\dfrac{259.19}{5280}= 0.0490890151515\approx0.049\text{ miles}$

8 0

4 years ago

3. Suppose that an airplane flying 60 m/s, at a height of 300m, dropped a sack of flour (pere the effect

Arlecino [84]

469.24m. An airplane flying 60m/s at a height of 300m dropped a sack of flour that stack the ground 469.24m from the point of release.

This is a example of horizontal parabolic projectile motion,and we represents this motion in the coordinate axis, which means that the velocity has components in x axis and y axis.

The equation of components on the x axis.

$v_{0}x=\frac{x}{t}$ , where x is the distance and Vox the initial velocity before the drop

The equation of components on the y axis.

$y = v_{0}yt+\frac{gt^{2} }{2}$ , where y is the height, and the velocity in y component before the drop is 0, reducing the equation to $y = \frac{gt^{2} }{2}$

Clear t from both the equation of components on the x axis and the y axis:

$t=\frac{x}{v_{0} x}$ and $t=\sqrt{\frac{2h}{g}}$

Equating both equations and clearing the distance x:

$\frac{x}{v_{0} x}=\sqrt{\frac{2h}{g}}\\x={v_{0} x}\sqrt{\frac{2h}{g}}$

Substituting the values:

$x=60\frac{m}{s} \sqrt{\frac{2(300m)}{9.81\frac{m}{s^{2} } }}=469.24m$

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3 years ago

1. The strength coefficient and strain-hardening exponent of brass are 100,000 lb/in2 and 0.35 respectively. A cylindrical speci

aleksandr82 [10.1K]

To solve this problem we will apply the concepts of strain, flow stress and average flow stress to find the required data. We will start by calculating the Strain which is the logarithmic relationship between the longitudinal change. Later we will find the flow stress through the strength coefficient, the strain and the strain-hardening exponent. Finally with the found values it will be possible to find the average flow stress,

Now the strain is calculated with the logaritmic relation of the lengths.

$\epsilon = ln(\frac{1.5}{3.0})$