Question

Nothing can escape the event horizon of a black hole, not even light. You can think of the event horizon as being the distance from a black hole at which the escape speed is the speed of light, 3.00 * 108 m/s, making all escape impossible. What is the radius of the event horizon for a black hole with a mass 5.0 times the mass of the sun? This distance is called the Schwarzschild radius.

Answer 1

Answer:

14740.7 m

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = $5\times 1.989\times 10^{30}\ kg$

c = Speed of light = $3\times 10^8\ m/s$

Schwarzschild radius is given by

$R=\dfrac{2GM}{c^2}\\\Rightarrow R=\dfrac{2\times 6.67\times 10^{-11}\times 5\times 1.989\times 10^{30}}{(3\times 10^8)^2}\\\Rightarrow R=14740.7\ m$

The radius of the event horizon of the black hole is 14740.7 m