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larisa [96]
1 year ago
11

How would you position a flat loop of wire in a changing magnetic field so that there is no induced emf in the loop?

Physics
1 answer:
devlian [24]1 year ago
8 0

Position the loop so that the field lines run perpendicular to the area vector or parallel to the surface so that there is no induced EMF in the loop

Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.

Flux is the presence of a force field in a specified physical medium, or the flow of energy through a surface. In electronics, the term applies to any electrostatic field and any magnetic field . Flux is depicted as "lines" in a plane that contains or intersects electric charge poles or magnetic poles.

As we all know that a moving charged particle will experience force by a magnetic field, the magnetic field produced by the field coil remains constant, that is, no force is experienced by electrons of the wire. So, we have to produce a relative motion between magnetic field and electrons.

Whenever the flux passing through the coil changes by any way (like either changing angle, magnetic field or area of coil), we are actually producing a relative motion between electrons and magnetic field. As a result, the electrons experience a magnetic force and shift to produce

flux =  \int\limits {BAcos(theta)} \,

theta = angle between magnetic field and area

Since we know , EMF get induced only when flux changes , if their is no flux change , no EMF can be induced

Hence , in order to not induce any kind of EMF ,we need to maintain a constant flux , but in question it is a changing magnetic field which means changing flux ,in this situation we need to align a flat loop parallel to magnetic field so , their is zero flux through the loop .

To learn more about flux here

brainly.com/question/14527109

#SPJ4

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To solve the exercise it is necessary to apply the equations necessary to apply Newton's second law and the concept related to frictional force.

An angle of 30 degrees is formed on the vertical at an applied force of 2.3N

In this way the frictional force, opposite to the movement will be given by

f_k = \mu_k N

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