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larisa [96]
1 year ago
11

How would you position a flat loop of wire in a changing magnetic field so that there is no induced emf in the loop?

Physics
1 answer:
devlian [24]1 year ago
8 0

Position the loop so that the field lines run perpendicular to the area vector or parallel to the surface so that there is no induced EMF in the loop

Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.

Flux is the presence of a force field in a specified physical medium, or the flow of energy through a surface. In electronics, the term applies to any electrostatic field and any magnetic field . Flux is depicted as "lines" in a plane that contains or intersects electric charge poles or magnetic poles.

As we all know that a moving charged particle will experience force by a magnetic field, the magnetic field produced by the field coil remains constant, that is, no force is experienced by electrons of the wire. So, we have to produce a relative motion between magnetic field and electrons.

Whenever the flux passing through the coil changes by any way (like either changing angle, magnetic field or area of coil), we are actually producing a relative motion between electrons and magnetic field. As a result, the electrons experience a magnetic force and shift to produce

flux =  \int\limits {BAcos(theta)} \,

theta = angle between magnetic field and area

Since we know , EMF get induced only when flux changes , if their is no flux change , no EMF can be induced

Hence , in order to not induce any kind of EMF ,we need to maintain a constant flux , but in question it is a changing magnetic field which means changing flux ,in this situation we need to align a flat loop parallel to magnetic field so , their is zero flux through the loop .

To learn more about flux here

brainly.com/question/14527109

#SPJ4

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If x=2/3and y=3/2, then find value of (x + y) divided by (x-y)<br><br>​
Reika [66]

Answer:

-13/5

Explanation:

13/6÷(-5/6)

-13/5

8 0
3 years ago
Why must the difference between the water level in the eudiometer tube and the water level in the beaker be measured
Bas_tet [7]

Answer:

Explanation:

The difference between the water level in the eudiometer tube and the water level in the beaker must be measured because we have to put into consideration, the pressure of the gases in the eudiometer tube. This said pressure of gas in the eudiometer must equal the atmospheric pressure. If or by chance, the water levels happens not to be at the same height, then this is not the case. And then, as a result, in order to account for the difference between both, while also being able to get accurate results, you have to find the difference or subtract the water levels and then go ahead in converting them to mmHg.

3 0
3 years ago
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 43.
zmey [24]

To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

\tau = r F

Here,

r = Radius

F = Force

Now the units,

r = 1.95cm = 1.95*10^{-2}m

Replacing,

\tau = (1.95*10^{-2})(43.5N)

\tau = 0.8483N\cdot m

Therefore the torque that the muscle produces on the wrist is 0.85N\cdot m

3 0
4 years ago
Why do electron microscopes have higher resolving power than light microscopes?
nikdorinn [45]
Electrons have a smaller wavelength than visible light, leading to higher resolution.
3 0
3 years ago
An artillery shell is fired with an initial speed of 300m/s at 55 deegry about the horizontal,it explodes on a mountain side 42s
photoshop1234 [79]

Answer:

x = 7226.94 m

y = 1677.4 m

Explanation:

This is a classic problem of a parabolic move. Let's analyze the given data.

The speed is 300 m/s but it's fired at 55°, so the x and y component of the speed would be:

Vx = 300 cos55 = 172.07 m/s

Vy = 300 sin55 = 245.75 m/s

Now, to get the x and y components of the shell, we need to apply the following expressions:

X = Xo + Vx*t    (1)

Y = Yo + Vy*t - 1/2 gt²   (2)

Xo and Yo is 0, and we already have the speed in x and y, so the components are:

X = 0 + (172.07)(42)

<h2>X = 7226.94 m</h2>

For the y component:

Y = 0 + (245.75)(42) - 1/2 (9.8)(42)²

Y = 10321.5 - 8643.6

<h2>Y = 1677.4 m</h2><h2></h2>

Hope this helps

8 0
3 years ago
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