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Sergeeva-Olga [200]
1 year ago
8

A patient has an order for a drug to be infused at the rate of 5 mcg/kg/min. A 500 ml bag contains 250 mg of the drug and the pa

tient weighs 185 pounds. An infusion set with a drop factor of 20 is being used. What is the flow rate in gtts/min
Physics
1 answer:
enot [183]1 year ago
3 0

The flow rate is 17gtts/min.

<h3>What is the drug infusion rate?</h3>
  • The rate of infusion (or dosing rate) in pharmacokinetics refers to the ideal rate at which a drug should be supplied to achieve a steady state of a fixed dose that has been shown to be therapeutically effective. This rate is not only the rate at which a drug is administered.
  • The infusion volume is divided into drops, which is known as a drip-rate. The Drip Rate formula is as follows: Volume (mL) times time (h) equals drip-rate. A patient must get 1,000 mL of intravenous fluids over the course of eight hours.
  • Infusion rates of 3–4 mg/kg per minute are advised by manufacturers to reduce rate-related adverse effects. Usually, the infusion lasts for several hours. Although not advised, rates exceeding 5 mg/kg per hour may be tolerated by some patients.
  • If no negative reactions occur, the rate may be increased in accordance with the table every 30 minutes up to a maximum rate of 3 ml/kg/hour (not to exceed 150 ml/hour).

To find the flow rate is 17gtts/min:

\frac{18 units}{h} \frac{100ml}{100units} \frac{500ml}{250mg} \frac{1mg}{1000mgc} \frac{20gtts}{ml} =\frac{17gtts}{min}

Therefore, The flow rate is 17gtts/min.

To learn more about infusion rate, refer to:

brainly.com/question/22761958

#SPJ9

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An air-track glider attached to a spring oscillates between the 14.0 cm mark and the 71.0 cm mark on the track. The glider compl
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Answer:

     A = 2,8333  s

Explanation:

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6 0
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In a solid , the atoms are tightly locked in position an do not change posistion , true or false
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Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide
velikii [3]

Answer:

  k_max = 31.82 w/mk

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Explanation:

a) the maximum thermal conductivity is given as

k_{max} = k_m*v_m + k_p*v_p

where k_m is thermal conductvitiy of metal

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v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

            = 66*0.17 + 28*0.83

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b) the minimum thermal conductivity is given as

k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}

          = \frac{28+66}{28*0.17 +66*0.83}

       k_min  = 17.70 w/mk

7 0
3 years ago
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