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Komok [63]
4 years ago
13

The law of reflection states that light is reflected off a surface at the same angle that light hits the surface. The arrow on t

he right of the diagram that shows the direction of light is the a
Question 4 options:

a.incident ray


b.refracted ray


c.coincident ray


d.reflected ray
Physics
2 answers:
kap26 [50]4 years ago
7 0

A. Incident ray is the answer

Yuliya22 [10]4 years ago
6 0

Answer:

a

Explanation:

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Select all that apply. Which of the following astronomers supported the Earth-centered system?
Stella [2.4K]
Among the options, the two astronomers who supported the Earth-centered system were Tycho Brahe and Ptolemy.

Both astronomers developed in fact a system where the Sun was located at the center, while the Earth and the other planets were orbiting around the Sun.
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4 years ago
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A 0.45-m metal rod moves 0.11 m in a direction that is perpendicular to a 0.80-T magnetic field in an elapsed time of 0.036 s. A
Gwar [14]

Answer:

1.1 V

Explanation:

L = 0.45 m

d = 0.11 m

B = 0.80 T

t = 0.036 s

Let e be the emf.

e = B v L

e = 0.80 x 0.11 x 0.45 / 0.036 = 1.1 V

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4 years ago
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What is the kinetic energy of a 200 kg satellite as it follows a circular orbit of radius 8x106m around the earth?
motikmotik
Given the equation for the Speed of a Satellite

v = SqRt{Gravitational Constant}{Mass of Earth} divided by the radius given in your problem

we have:


(square root whole term on right side)

v = G Me
———
r


so. (6.67x10^-11)(5.97x10^24)
___________________
(8.0x10^6)


v = 7055 m/s (which is reasonable)


so utilize the Kinetic Energy Formula


KE = 1/2mv^2


KE = 1/2(200)(7055)^2


KE = 4.977x10^9 J


4 0
3 years ago
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Where are warm air vents usually located in a forced air heating system
crimeas [40]
The system is located in the HairyFunyon aka near the floor
8 0
4 years ago
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In an elastic collision, a 580 kg bumper car collides directly from behind with a second, identical bumper car that is traveling
kozerog [31]

Answer:  vl = 2.75 m/s vt = 1.5 m/s

Explanation:

If we assume that no external forces act during the collision, total momentum must be conserved.

If both cars are identical and also the drivers have the same mass, we can write the following:

m (vi1 + vi2) = m (vf1 + vf2) (1)

The sum of the initial speeds must be equal to the sum of the final ones.

If we are told that kinetic energy must be conserved also, simplifying, we can write:

vi1² + vi2² = vf1² + vf2² (2)

The only condition that satisfies  (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:

vf1 = vi2 and vf2 = vi1

If we call v1 to the speed of the leading car, and v2 to the trailing one, we can finally put the following:

vf1 = 2.75 m/s  vf2 = 1.5 m/s

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