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Veseljchak [2.6K]
1 year ago
15

The Haber process is a method to produce ammonia from hydrogen and nitrogen gases. The reaction is:

Chemistry
1 answer:
Damm [24]1 year ago
5 0

Answer:

D.) Shift to the right to produce more product

Explanation:

When more reactants are added to a reaction, the equilibrium will shift to the product side to restore the balance.

As such, when H₂ (a reactant) is added, the reaction will shift to the product side, resulting in an increase of NH₃.

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A student attempted to identify an unknown compound by the method used in the experiment. She found that when she heated the sam
yanalaym [24]
Na2CO3 + 2Cl- ⇒ 2NaCl + CO3^-2 
<span>
1 mole of Na2CO3 = 106 g </span>
<span>2 moles of NaCl     = 2 x 58.4
                               = 116.8 g 
</span>Na2CO3 would increase by 116.8 / 106 = 1.10 to form 2NaCl.
<span>0.4862 g x 1.10 = 0.515 grams of NaCl.
</span>
K2CO3 + 2Cl- ⇒ 2KCl + CO3^-2 
<span>1 mole of K2CO3 = 138.2 g </span>
<span>2 moles of KCl = 149.1 </span>
<span>
K2CO3 would increase by </span>149.1 /138.2 = 1.079 <span>to form 2KCl
</span>
<span> 0.4862 x 1.079 = 0.5246 g</span>


3 0
3 years ago
Read 2 more answers
How can you make a solution saturated?
liubo4ka [24]
You can make a solution saturated by Adding more solute. Hope this helps, good luck. 
8 0
3 years ago
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calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w
kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is -22Jmole^-^1k^-^1

(b) The normal boiling point of water (J·K−1·mol−1) is -109Jmole^-^1K^-^1

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is  109J/mole

Explanation:

Lets calculate

(a) - General equation -

      (\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p = -5_m(\beta )+5_m(\alpha ) =  -\frac{\Delta H}{T}

 \alpha ,\beta → phases

ΔH → enthalpy of transition

T → temperature transition

 (\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p == -\frac{\Delta_fH}{T_f}

            = \frac{-6.008kJ/mole}{273.15K} ( \Delta_fH is the enthalpy of fusion of water)

           = -22Jmole^-^1k^-^1

(b) (\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}

                                  = \frac{40.656kJ/mole}{373.15K} (\Delta_v_a_p_o_u_rH is the enthalpy of vaporization)

                               = -109Jmole^-^1K^-^1

(c) \Delta\mu =\Delta\mu(l)-\Delta\mu(s) =-S_m\DeltaT

[\mu(l-5°C)-\mu(l,0°C)] =  [\mu(s-5°C)-\mu(s,0°C)]=-S_mΔT

\mu(l,-5°C)-\mu(s,-5°C)=-Sm\DeltaT [\mu(l,0

\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)

     = 109J/mole

6 0
2 years ago
Science pls help me having trouble on the third one
Ira Lisetskai [31]
The diameters of the spheres are 72.5 meters square
6 0
3 years ago
Read 2 more answers
Calculate the time it takes for an object moving with a speed of 13m/s to travel 50 m
kykrilka [37]

Answer:

<h3>The answer is 3.85 s</h3>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance covered

v is the velocity

From the question we have

t =  \frac{50}{13}  \\  = 3.846153...

We have the final answer as

<h3>3.85 s</h3>

Hope this helps you

7 0
3 years ago
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