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3 years ago

Explain how pressure affects a scuba diver rising to the surface

1 answer:

8 0

When underwater a diver is under greater pressure then when at the surface of the water and the deeper you go down the higher the pressure. A diver is also inhaling pure pressurized oxygen so when they begin to go up toward the surface of the water the pressure on the diver is lessened which causes the gases in the blood stream to expand, most particularly nitrogen gas, due to the lower amounts of experienced pressure and the higher concentration of oxygen in the blood stream. Now if the diver surfaces to rapidly the expanding gas can travel to the brain damaging it and/or rupturing blood vessels which can cause hemorrhaging which in turn can cause death. The situation where a diver surfaces too quickly and the expanded gas damages their brain is called The Bends.

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Fecl3 reacts with only one of the two compounds aspirin and salicylic acid with which part of a molecule does fecl3 react

lara [203]

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3 years ago

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A gas sample at stp contains 1.15 g oxygen gas and 1.55 g nitrogen gas.what is the volume of the gas sample?

ss7ja [257]

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3 years ago

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What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

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ValentinkaMS [17]

Its either A or B, 50-50 chance?

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