Explain how pressure affects a scuba diver rising to the surface

1 answer:

8 0

When underwater a diver is under greater pressure then when at the surface of the water and the deeper you go down the higher the pressure. A diver is also inhaling pure pressurized oxygen so when they begin to go up toward the surface of the water the pressure on the diver is lessened which causes the gases in the blood stream to expand, most particularly nitrogen gas, due to the lower amounts of experienced pressure and the higher concentration of oxygen in the blood stream. Now if the diver surfaces to rapidly the expanding gas can travel to the brain damaging it and/or rupturing blood vessels which can cause hemorrhaging which in turn can cause death. The situation where a diver surfaces too quickly and the expanded gas damages their brain is called The Bends. <span />

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Which of the following methods for increasing the rate of chemical reaction increases the effectiveness of the interactions betw

denpristay [2]

Answer:

Increasing the surface area of the reactants

Explanation:

An increase in surface area of the reactant will always cause an increase in the rate of reaction. This is so because, an increase in the surface area of the reactant will cause the reactant particles to collide effectively thereby bringing about an increase in the reaction rate.

Collision theory suggests that for a reaction to occur, the reactant particles must collide with the right orientation. As the surface area of the reactants are increased, the reactants particles collide more with the right orientation bringing about definite increase in the rate of reaction.

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vladimir2022 [97]

Since each Chlorine molecule is -1 and wants to gain an electron, 2 Chlorine atoms like to come together to form Cl2 by sharing 2 electrons each to form a single bond between the 2 atoms. Since both Chlornine has the same electronegativity, the bond is non-polar covalent since there electrons are evenly shared.

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A student balances the following redox reaction using half-reactions.

ICE Princess25 [194]

Answer: 6.

Explanation:

1) Aluminum

$Al^0-3e^----\ \textgreater \ Al^{3+}$

So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.

2) Manganesium

$Mn^{2+}+2e^{-}---\ \textgreater \ Mn$

So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.

3) Balance

Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:

$2Al^{0}-6e^{-}---\ \textgreater \ 2Al^{3+}

3Mn^{2+}+6e^{-}---\ \textgreater \ 3Mn^{0}$

4) Net equation

Add the two half-equations:

$2Al^{0}+3Mn^{2+}----\ \textgreater \ 2Al^{3+}+3Mn^{0}$

As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.

The right side has 2 Al, 3 Mn, and 2*3 positive charges.

So, the equation is balanced.

5) Count the number of electrons involved.

As you see 2 atoms of aluminum lost 6 electrons (3 each).

That is the answer to the question. 6 electrons will be lost.

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irinina [24]

Answer: Opaque hope this is helpful

Send a brainliest if this was helpful :)

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Answer:

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Explanation:

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