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1 year ago

What is the structure of polypropylene

Chemistry

1 answer:

pantera1 [17]1 year ago

8 0

The Structure of polypropylene(C3H6)n is linear.

The chemical formula for polypropylene is (C3H6)n.
It is a polymer with complex structure and also known as polypropene.
Polypropylene is similar to polyethylene which belongs to polyolefin groups.
Generally the polymers are synthesized from the polymerization process.
What is polymerization?

The process in which atom or small molecules joined together repeatedly to form a polymer with complex structure is called as polymerization.

The repeated unit of atom or small molecule is called monomer

<h3>Structure of polypropylene</h3>

Polypropylene is synthesized from the polymerization of propylene which is the monomer unit.

It has a linear structure made of propylene hydrocarbon units.

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What is a saturted solution

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Answer:

Please find the definition and further explanation below

Explanation:

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3 years ago

The lowest energy state of an atom is its

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4 years ago

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Using the following thermochemical data, what is the change in enthalpy for the following reaction?

slavikrds [6]

Answer:

D. -120.9 kJ

Explanation:

According to Hess's law ,the total enthalpy change for a reaction is the sum of all changes regardless of the stages or the steps of the reaction.

$CaO + 2HCl \rightarrow CaCl_{2} + H_{2}O\ (\Delta H = -186\ kJ)$ ....(1)

$CaO + H_{2}O\rightarrow Ca(OH)_{2}\ (\Delta H = - 65 \ kJ)$

(this reaction should be reversed in order to reach the required reaction )

On reversing the reaction the sign of $\Delta H$ get reversed.

(In this case change sign from '-' to'+'. Hence $\Delta H$ = + 65 kJ)

$CaO + 2HCl \rightarrow CaCl_{2} + H_{2}O\ (\Delta H = - 186\ kJ)$ ....(1)

$Ca(OH)_{2} \rightarrow CaO + H_{2}O\ (\Delta H = + 65 kJ )$ ......(2)

Adding equation (1) and (2)

$Ca(OH)_{2} + 2HCl \rightarrow CaCl_{2} + 2H_{2}O[tex][tex]Delta H = - 186 + 65 = - 121\kJ$

$Delta H = - 121\kJ$ (It is nearly equal to -120.9 kJ)

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3 years ago

A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density?

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3 years ago

Consider the following reactions: 1. 2 SO3(g) ⇄ 2 SO2(g) + O2(g) K 1 = 2.3 × 10-7 2. 2 NO3(g) ⇄ 2 NO2(g) + O2 (g) K 2 = 1.4× 10-

juin [17]

Answer:

K =78

Explanation:

Step 1: Data given

2SO3(g) <--> 2SO2(g) + O2(g) kc = 2.3 x 10^-7

2NO3(g) <--> 2NO2(g) + )2(g) kc = 1.4 x 10^-3

Step 2: Calculate K

Lets write out the two reactions in the proper order and look at how they sum together:

2 SO2(g) + O2(g) <---> 2 SO3(g) (1)

2NO3(g) <---> 2 NO2(g) + O2(g) (2)

The two reactions as now written give us the correct reactants and products on the correct sides of the reaction arrow.

Since we have O2 as both a reactant and a product, we can cancel O2 and are not part of the final overall reaction equation.

Koverall = Kc1 * Kc2

Because we reversed reaction number 1 this affects its Kc via the following:

Krev = 1/Kfwd.

We then replace Kc1 with its value for the reverse direction.

So Koverall now = (1/Kfwd) * Kc2

The sum of the two reactions above gives us:

2 SO2(g) + 2 NO3(g) <---> 2 SO3(g) + 2 NO(g)

The problem states to give the K value for the reaction where all the numbers in front of the molecules are (1), and we have (2)'s. So basically if we multiply the whole reaction by 1/2 we'll get the final overall equation we want.

1/2 ( 2 SO2(g) + 2 NO3(g) <----> 2 SO3(g) + 2 NO(g) )

So Kfinal = (Koverall)^1/2

K = ( 1/Kfwd * Kc2)^1/2

K = ( [1 / 2.3 * 10^-7] * 1.4 * 10^-3)^1/2

K =78

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3 years ago