Answer:
Mass = 57.05 g
Explanation:
Given data:
Volume of SO₂ = 20.0 L
Temperature = standard = 273 K
Pressure = standard = 1 atm
Mass of SO₂ = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 20.0 L / 0.0821 atm.L/ mol.K× 273 k
n = 20.0 / 22.41/mol
n = 0.89 mol
Mass of SO₂:
Mass = number of moles × molar mass
Mass = 0.89 mol × 64.1 g/mol
Mass = 57.05 g
Answer:
A. 336 L
Explanation:
STP is 0 °C and 1 bar.
At STP, the molar volume of a gas is 22.71 L.
Volume = 15 mol × 22.71 L/mol
Volume = 341 L
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The above answer is not in your list of options.
It appears that you are using the <em>OLD</em> (pre-1982) definition of STP, at which the molar volume of a gas is 22.4 L.
Then
V = 15 mol × 22.4 L/mol = 336 L
Answer:
give us something else to work with or this is just the best guess
Answer:
Answer is in the explanation.
Explanation:
For the reaction:
Ba₃(PO₄)₂(aq) + 3Na₂SO₄(aq) → 3BaSO₄(s) + 2Na₃PO₄(aq)
As Na₂SO₄(aq) is in excess, limiting reactant is Ba₃(PO₄)₂(aq). As the molarity of the solution is 0,25M and you knew the volume of the solution, you can obtain the moles of Ba₃(PO₄)₂ doing 0,25M×volume.
As 1 mol of Ba₃(PO₄)₂(aq) react with 3 moles of BaSO₄ the moles of BaSO₄ are three times moles of Ba₃(PO₄)₂.
As BaSO₄ molar mass is 233,38g/mol. The mass of BaSO₄ is given by moles of BaSO₄ × 233,38g/mol
I hope it helps!
Hey there!:
That depends on the pH of the water layer. If the water layer is basic or rather just not acidic, it will be in the water layer. If the water layer is acidic, pH 4 or less, it will be in the ether layer. On the question of upper and lower, either has a density of less than one so it will be the upper layer.
