The catalyst (4) decreases the activation energy required for a reaction, by holding reactants in place
Answer:
d. To the left because Q > K_p
Explanation:
Hello,
In this case, for the given reaction:

The pressure-based equilibrium expression is:

In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:

Therefore, since Q>Kp we can see that there are more products than reactants, which means that the reaction must shift leftwards towards the reactants in order to reestablish equilibrium, thus, answer is d. To the left because Q > Kp.
Regards.
Answer:
An elementary particle that is identical with the nucleus of the hydrogen atom, that along with the neutron is a constituent of all other atomic nuclei, that carries a positive charge numerically equal to the charge of an electron.
Example:
The nucleus of a hydrogen atom or the H+ ion is an example of a proton. Regardless of the isotope, each atom of hydrogen has 1 proton; each helium atom contains 2 protons; each lithium atom contains 3 protons and so on.
Electronegativity measures how much an atom likes to pull electrons away from another one. Ionization energy measures how much an atom doesn't want to lose electrons. As an atom that wants to gain electrons will clearly not want to lose electrons, these trends are basically identical.