Answer:
3.5 × 10⁵ g of salt
Explanation:
<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>
We have this data:
- 1.000 mol salt is equal to 58.44 g salt
- 1.0 L of ocean water contains 0.60 mol of salt
We will need the following relations:
We can use proportions:
Answer:
Benzene must be kept away from flames.
Explanation:
Edge2020
The intermolecular forces that are responsible for the dissolution of Ethylene glycol in water is hydrogen bonding dipole-dipole forces and dispersion forces.
Both ethylene glycol and water contains the pair of hydrogen and oxygen.
The hydrogen of one atom create a bond with the oxygen of other atom this results in the formation of intra molecular hydrogen bonding.
The electron are non uniformly distributed over the molecule or the atom which results in the fluctuation of the electron density in the atom.
So it creates are dispersion forces which is present all over the molecule this forces helps to increase the strength of the bond formed between the ethylene glycol and water because they have large masses.
Both ethylene glycol and water are polar molecules because of being polar they form dipole and the dipole of both the molecules interact with each other in order to form bond between the atoms which eventually results in the formation dissolution of ethylene glycol in water.
To know more about intermolecular forces, visit,
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Compete Question - which intermolecular forces are responsible for the dissolution of ethylene glycol? select all that apply hydrogen bonding, dipole-dipole, dispersion and Ion dipole interaction.
For the answer to the question above, <span>17.9 x 1.74 gram Mg = 31.15 gram Mg = (31.15/24.31) = 1.28 mole Mg </span>
<span>2 Mg + O2 ---> 2MgO </span>
<span>so 1.28 mole Mg reacts with 0.641 mole O2
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
The pressure of the gas is 2700 mmHg.
To solve this problem, we can use the <em>Combined Gas Laws</em>:
(<em>p</em>_1<em>V</em>_1)/<em>T</em>_1 = (<em>p</em>_2<em>V</em>_2)/<em>T</em>_2
<em>p</em>_2 = <em>p</em>_1 ×<em> V</em>_1/<em>V</em>_2 × <em>T</em>_2/<em>T</em>_1
<em>T</em>_2 = (-55+273.15) K = 218.15 K; <em>T</em>_1 = (33+273.15) K = 306.15 K
<em>p</em>2 = 760 mmHg × (0.50 m^3/0.10 m^3) × (218.15 K/306.15 K) = 2700 mmHg
