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zalisa [80]
3 years ago
5

Can somebody try and answer 1 of these questions also for 5 answer in 3 sentences thx!!!!

Chemistry
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

Comparative Anatomy:

5. Comparative anatomy is the comparative study of the body structures of different species of animals in order to understand the adaptive changes they have undergone in the course of evolution from common ancestors.

One way whales are different from fish is:

1) Whales actually breathe air with lungs using their blowholes to breath out!. Fish get oxygen directly from the water through their gills.

Hope this helps! :D

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Which is the larger atom S or Mg
Vadim26 [7]

Answer:

Mg

Explanation:

If one were comparing just the neutral atoms Mg and S, the S atom would be smaller as both elements are in the same period and sulfur is more to the right

8 0
3 years ago
So2−3(aq)→so2−4(aq) (basic solution) express your answer as a chemical equation. identify all of the phases in your answer. so32
alexira [117]

Answer:

SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

Explanation:

The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:

Chemical equation: SO_{3}^{2-}(aq.)\rightarrow SO_{4}^{2-}(aq.)

Balance H and O in basic medium: SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)

Balance charge: SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

Balanced chemical equation:

SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

6 0
3 years ago
How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr
JulsSmile [24]

Answer: 403ml

Explanation:

M=\frac{mol}{L}

Solve for L;

L=\frac{mol}{M}\\L=\frac{0.0867mol}{0.215M}\\ L=0.403L

Convert to mililiters

0.403L(\frac{1000ml}{1L})=403ml

3 0
3 years ago
Which change occurs at the anode in an operating electrochemical cell?
murzikaleks [220]

Answer:loss of electrons

Explanation:

6 0
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PLEASE HELP!!
VLD [36.1K]

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