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2 years ago

U= (-5,3) find the magnitude of u. please help me

Physics

1 answer:

Fantom [35]2 years ago

3 0

u = 5.83

Explanation:

The magnitude of a vector $\vec{u}$ is

$|\vec{u}| = \sqrt{u_z^2 + u_y^2} = \sqrt{(-5)^2 + (3)^2}$

$\:\:\:\:\:\:\:= \sqrt{34} = 5.83$

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Pls send the answer..pls...

Sophie [7]

Answer:

The fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

Explanation:

Given;

initial temperature of the liquid, t₁ = 76.3 +/- 0.4⁰C

final temperature of the liquid, t₂ = 67.7 +/- 0.3⁰C

The change in temperature of the liquid is calculated as;

Δt = t₂ - t₁

Δt = (67.7 - 76.3) +/- (0.3 - 0.4)

Δt = (-8.6) +/- (-0.1)

Δt = 8.6 +/- 0.1 ⁰C

Therefore, the fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

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3 years ago

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3 years ago

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3 years ago

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ch4aika [34]

Answer:

g'(10) = $\frac{-1}{16}$

Explanation:

Since g is the inverse of f ,

We can write

g(f(x)) = x (Identity)

Differentiating both sides of the equation we get,

g'(f(x)).f'(x) = 1

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Now, we have to find x when f(x) = 10

Thus 10 = $\frac{4}{x}$ + 2

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x = $\frac{1}{2}$

Since f(x) = $\frac{4}{x}$ + 2

f'(x) = - $\frac{4}{x^{2} }$

f'( $\frac{1}{2}$ ) = -4 × 4 = -16

Putting it in equation 1, we get:

We get g'(10) = - $\frac{1}{16}$

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3 years ago

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Answer:

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3 years ago