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elena-14-01-66 [18.8K]
4 years ago
7

Pls help me idk what to do

Physics
1 answer:
Alika [10]4 years ago
6 0
The dot would be the earthquake epicenter. That is where the earthquake originated.
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Please solve this for me ​
uranmaximum [27]

See if you get the answer with this formulae.

6 0
3 years ago
What do scientists do to easily share measurement data they can understand?
malfutka [58]
These days, scientists all over the world use a standard system of measurements.  It's the SI or metric system.

What about scientists in the United States, Liberia, and Burma ? 
These three countries are the only ones in the world that haven't
adopted the metric system.  What do THEY do ?

Easy.  When scientists in those countries are off work, they use the
inches, yards, feet, quarts, miles and gallons that everybody around
them is using.  But when they go to work, they use the same metric
system that everyone else in the world is using.
3 0
4 years ago
Read 2 more answers
In tenis does your knees have to be slightly flexed for both the forehand and backhand?
Elena L [17]

Answer:

yes

Explanation:

8 0
3 years ago
A package of mass 5 kg sits on an airless asteroid of mass 7.6 × 1020 kg and radius 8.0 × 105 m. We want to launch the package i
Effectus [21]

Answer:

s =  1.7 m

Explanation:

from the question we are given the following:

Mass of package (m) = 5 kg

mass of the asteriod (M) = 7.6 x 10^{20} kg

radius = 8 x 10^5 m

velocity of package (v) = 170 m/s

spring constant (k) = 2.8 N/m

compression (s) = ?

Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore  

• Ei = Ef

• Ei = energy in the spring + gravitational potential energy of the system

• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}

• Ef = kinetic energy of the object

• Ef = \frac{1}{2}mv^{2}  

• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}  

• s = \sqrt{\frac{m}[k}(v^{2}+\frac{2GM}{r})}

s = \sqrt{\frac{5}[2.8 x 10^5}(170^{2}+\frac{2 x 6.67 x10^{-11} x 7.6 x 10^{20}}{8 x 10^5})}

s =  1.7 m

7 0
3 years ago
Your code returns a number of 99.123456789 +0.00455679 for your calculation. How should you report it in your lab write-up?
Aneli [31]

Answer: Your code returns a number of 99.123456789 +0.00455679

Ok, you must see where the error starts to affect your number.

In this case, is in the third decimal.

So you will write 99.123 +- 0.004 da da da.

But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.

in the error, after the 4 comes a 5, so it rounds up.

So the final presentation will be 99.123 +- 0.005

you are discarding all the other decimals because the error "domains" them.

6 0
3 years ago
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