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elena-14-01-66 [18.8K]
4 years ago
7

Pls help me idk what to do

Physics
1 answer:
Alika [10]4 years ago
6 0
The dot would be the earthquake epicenter. That is where the earthquake originated.
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The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weigh
Serjik [45]

Answer:

89.16pounds

Explanation:

The equation that defines this problem is as follows

W=k/X^2

where

W=Weight

K= proportionality constant

X=distance from the center of Earth

first we must find the constant of proportionality, with the first part of the problem

k=WX^2=131x3960^2=2054289600pounds x miles^2

then we use the equation to calculate the woman's weight with the new distance

W=2054289600/(4800)^2=89.16pounds

4 0
3 years ago
The electric current in a wire is 1.5A. How many electrons flow past a given point in a time of 2s?
kipiarov [429]

Answer:

The amount of electrons that flow in the given time is 3.0 C.

Explanation:

An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.

i.e           I = \frac{Q}{t} ...................(1)

It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.

In the given question, I = 1.5A, t = 2s, find Q.

From equation 1,

            Q = I × t

                = 1.5 × 2

               = 3.0 Coulombs

The amount of electrons that flow in the given time is 3.0 C.

5 0
3 years ago
The moon has a mass of 7.35x1022 kg and is a lot farther away than is shown in textbooks. The mass of the
anyanavicka [17]

Answer:

F=1.98\times 10^{20}\ N

Explanation:

Given that,

The mass of a Moon, M_m=7.35\times 10^{22}\ kg

The mass of the Earth, M_e=5.98\times 10^{24}\ kg

The moon's mean orbit distance around the earth is, r=3.84\times 10^8\ m

We need to find the gravitational force exerted on the moon by the Earth.

The formula of gravitational force is given by :

F=G\dfrac{M_mM_e}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{7.35\times 10^{22}\times 5.98\times 10^{24}}{(3.84\times 10^8)^2}\\\\F=1.98\times 10^{20}\ N

So, the required force is 1.98\times 10^{20}\ N.

3 0
3 years ago
200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?
ArbitrLikvidat [17]

Answer:

 20N

Explanation:

Given parameters:

Work done  = 200J

Distance moved  = 10m

Unknown:

Amount of force applied  =?

Solution:

Work done is the force applied on a body to move it in the direction of the force.

      Work done  = force x distance

The unit of work done is in joules

Since the unknown is force, we make it the subject of the expression;

           Force  = \frac{Work done}{distance}

           Force  = \frac{200}{10}   =  20N

5 0
4 years ago
Imagine that someone is walking across a carpeted room and then touches a metal doorknob. Describe what happens when a doorknob
mr_godi [17]

Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process

Explanation:

7 0
3 years ago
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