a = dv/t = (330-x)/1.5 =50
x= 330-75 = 255 m/s
Intial velocity 255 m/s
Alter (a number) to one less exact but more convenint calculations.
Answer:
Explanation:
The two examples of contact forces are frictional force and applied force. The two examples of noncontact forces are gravitational force and magnetic force.
In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
= (5 * 10) Kg m/s
= 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
Linear velocity and angular velocity are related by the formula:
v = ωr
ω = n2πr/t, where n is the number of rotations, t is the time taken, r is the radius.
ω = 2 x 2π x 25/1
ω = 100π
v = 100π x 25
= 2500π feet per minute
