Answer:
a) -1.25 rev/s² and 23.3 rev
b) 2.67s
Explanation:
a) ω
= (500 rev/min)(1min/ 60s) => 8.333 rev/s
ω
= (200 rev/min)(1min/ 60s) => 3.333rev/s
time 't'= 4 s
angular acceleration 'α'=?
constant angular acceleration equation is given by,
ω= ω + αt
α= (ω - ω )/t => (3.333-8.333)/4
α= -1.25 rev/s²
θ-θ
= ω t + 1/2αt²
=(8.333)(4) + 1/2 (-1.25)(4)²
=23.3 rev
b) ω=0 (comes to rest)
ω = 3.333 rev/s
α= -1.25 rev/s²
ω= ω + αt
t= (ω - ω)/α => (0- 3.333)/-1.25
t= 2.67s
Answer: E/4 ( one - fourth of it electric field)
Explanation:
The electric field of a point charge is given below as
E =kq/r²
E = electric field,
K = electric constant
q = magnitude of electric charge
r = distance between point charge and electric field.
It can be seen that only E and r are the only variable here and also, E is inversely proportional to r²
Which implies that
E = k/r² , k = E × r²
E1 ×(r1)² = E2 × (r2)²
Let E1 = E, r1 =1, r2 = 2 and E2 =?
Let us substitute the parameters
E × 1 = E2 × 2²
E × 1 = E2 × 4
E = E2 × 4
E2 = E/4
Which implies that the electric field at the second distance (r =4) is one fourth of the initial electric field.
so, question number 10 answer is 82 watts
<span>The equilibrium position is that at which the pendulum is at its lowest point; it is called this because, absent any other forces acting upon it, this is the point at which the pendulum would be at a stable, motionless equilibrium. It is also the point at which the pendulum, having been released from above, has translated its starting gravitational potential energy fully into kinetic energy. As such, this means that at this point the pendulum is at its maximum D) velocity.</span>
