Answer:
a. 10.0 g
Explanation:
Hello.
In this case, for melting phase change, which is a physical change that allow the organized molecular arrangement of solid particles to spread and turn out into the spread molecular arrangement of liquids, we must take into account that the process is undergone by the entire mass then reaching the equilibrium (after some time).
Therefore as there ware 10.0 g of ice, then 10.0 g of liquid will remain after the melting process gets carried out, thus, answer is a. 10.0 g
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Best regards.
It takes 11.4 days⇒three half-lives
<h3>Further explanation
</h3>
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t1/2=3.8 days
No=4.38 μg
Nt=0.55 μg
Mass of BaO in initial mixture = 3.50g
Explanation:
Let mass of BaO in mixture be x g
mass of MgO in mixture be (6.35 - x) g
Initially CO_2
Volume = 3.50 L
Temp = 303 K
Pressure = 750 torr = 750 / 760 atm
Applying ideal gas equation
PV = nRT
n = PV / RT
(n)_CO_2 = ((750/760)* 3.50) / 0.0821 * 303
(n)_CO_2 = 0.139 mole
Finally; mole of CO_2
n= PV /RT
((245/760) *3.5) / 303* 0.0821
(n)_CO_2 = 0.045 mole
Mole of CO_2 reacted = 0.139 - 0.045
=0.044 mole
BaO + CO_2 BaCO_3
Mgo + CO_2 MgCO_3
moles of CO_2 reacted = ( moles of BaO + moles of MgO)
moles of BaO in mixture = x / 153 mole
moles of MgO in mixture = 6.35 - x mole / 40
Equating,
x/ 153 +6.35/40 = 0.094
= x/153 + 6.35 / 40 - x/40 =0.094
= x (1/40 - 1153) = (6.35/40 - 0.094)
= x * 10.018464
= 0.06475
mass of BaO in mixture = 3.50g
It is a mixture because it is made up of three different kinds of minerals, feldspar, quartz, and mica which are mixed together<span>
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