Gallium has 31 electrons (₃₁Ga 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p¹) and if loses 13 electrons, gallium would have configuration of noble gas argon with 18 electrons (₁₈Ar 1s² 2s² 2p⁶ 3s² 3p⁶), but that is not possible, so gallium only loses three electrons and has electron configuration:
₃₁Ga³⁺ 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰.
To find the formulae, you must add as many of the ions together to get a neutral charge. For example, one Li^+ ion and one NO2^- ion give LiNO2, which is lithium nitrite, but since CO3^2- has a charge of -2, it needs 2 Li^+ ions to make the neutral compound Li2CO3, lithium carbonate. Similarly, Cu^2+ needs 2 NO2^- ions to make the neutral compound Cu(NO2)2, copper(II) nitrite. To name these, simply add together the names of the ions used. Li^+ is lithium, Cu^2+ is copper(II), and Ba^2+ is barium. The negatively charged ions are named as nitrite for NO2^-, carbonate for CO3^2-, bisulfate for HSO4^- and phosphate for PO4^3-.
Answer: The final temperature of the gas is 7.58 °C.
Explanation: We are given initial and final pressure of the system and we need to find the final temperature of the system.
To calculate it, we use the equation given by Gay-Lussac.
His law states that pressure is directly related to the temperature of the gas.
Or,
where,
= initial pressure = 893 mmHg = 1.175atm (Conversion factor: 1atm = 760mmHg)
= initial temperature = 49.3°C = [49.3 + 273.15]K = 322.45K
= Final pressure = 778mmHg = 1.023atm
= Final temperature = ?°C
Putting values in above equation, we get:
Converting Final temperature from kelvin to degree Celsius.
![T_2=280.73K=[280.73-273.15]^oC=7.58^oC](https://tex.z-dn.net/?f=T_2%3D280.73K%3D%5B280.73-273.15%5D%5EoC%3D7.58%5EoC)
Hence, the final temperature of the gas is 7.58 °C.
<span>The answer is 8. Hope this help!!!
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