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cluponka [151]
3 years ago
15

I need help with this worksheet that's my homework, I would need help to do it all

Chemistry
1 answer:
kaheart [24]3 years ago
4 0
U can try to help you
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25<br> #of<br> protons<br> # of<br> neutrons<br> # of<br> electrons
Molodets [167]

Answer:

16

Explanation:

number of electrons should also be 16.

5 0
3 years ago
Explain why a solar eclipse occurs only during a new Moon
Gennadij [26K]
Because the moon gets between the Sun and the Earth so you can't see the moon
3 0
3 years ago
A student made an initial 1:5 dilution of protein lysate. Then 2mL of that was added to 8mL of water. Lastly, the student made a
Licemer1 [7]

Answer:

The final dilution is 1:400

Explanation:

Let's analyze what we are told: we have an initial 1:5 dilution of protein lysate. This means that the initial solution (stock solution) was diluted 5 times. Then, from this dilution the student prepared another dilution taking 2 mL of the first dilution in 8 mL of water. This is the same as saying we took 1 mL of first dilution in 4 mL of water (the ratio is the same), so we now have a second 1:4 dilution of the first dilution (1:5). Finally, the student made a third 1:20 dilution, this means that the second dilution was further diluted 20 times.

So, to calculate the final dilution of protein lysate, we have to multiply all the dilution factors of every dilution prepared: in this case we have a final dilution of 1:20, this means we have a factor dilution of 20. But it was previously diluted 4 times, so we have a factor dilution of 20×4 = 80. However, this dilution was also previously diluted 5 times, so the new dilution factor is 80 × 5 = 400

This means that the final dilution of the compound was diluted a total of 400 times compared to the initial concentration of stock solution.

3 0
2 years ago
For the titration of a weak acid with a strong base what is the pKa of the weak acid if the pH is 6.72 at the equilvalence point
Paladinen [302]

Explanation:

We have to calculate pK_{a} value.

It is known that at the equivalence point concentration of acid is equal to the concentration of anion formed.

Hence,         [HA] = [A^{-}]

Now, relation between pK_{a} and pH is as follows.

                   pH = pK_{a} + log \frac{[A^{-}]}{[HA]}

Putting the values into the above formula as follows.

                   pH = pK_{a} + log \frac{[A^{-}]}{[HA]}

                  4.23 = pK_{a} + log (1)            (as [HA] = [A^{-}])

                   pK_{a} = 4.23                (as log (1) = 0)

or,                   pK_{a} = 4

Thus, we can conclude that pK_{a} of given weak acid is 4.  

                   

6 0
3 years ago
What particles are found in the nucleus of an atom?
Nana76 [90]
It’s a neutrons and electrons
6 0
3 years ago
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