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Gnesinka [82]
3 years ago
13

What is the reaction of lead with sulphuric acid

Chemistry
1 answer:
vesna_86 [32]3 years ago
7 0
Lead reacts very slowly with dilute hydrochloric acid to give lead chloride<span> and </span>hydrogen<span> gas. </span>

<span>lead + hydrochloric acid —> lead chloride + hydrogen
Pb(s) + 2HCl(aq) —> PbCl2(aq) + H2(g)</span> 

<span>Lead reacts very slowly with dilute sulphuric acid to give </span>lead sulphate<span> and </span>hydrogen<span> gas. </span>

<span>lead + sulphuric acid —> lead sulphate + hydrogen
Pb(s) + H2SO4 (aq) —> PbSO4(aq) + H2(g)</span> 

<span>Lead reacts very slowly with dilute nitric acid to give </span>lead nitrate<span> and </span>hydrogen<span> gas. </span>

<span>lead + nitric acid —> lead nitrate + hydrogen
Fe(s) + 2HNO3(aq) —> Fe(NO3)2(aq) + H2(g)</span><span> </span>
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A chemist has some 40% acid solution, some 60% acid solution, and a wholebunch of free time. How many liters of each should be u
TiliK225 [7]

Answer:

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

Explanation:

Let volume of the 40% acid solution be x.

Let volume of the 60% acid solution be y.

Volume of solution formed after mixing both solution = 40 L

x + y = 40 L..[1]

Volume of acid 40% solution = 40% of x= 0.4x

Volume of acid 60% solution = 60% of y= 0.6y

Volume of acid formed = 45% of 40 L = \frac{45}{100}\times 40=18L

0.4x+0.6y=18 L..[2]

Solving [1] and [2]

x = 30 L  ,   y = 10 L

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

8 0
3 years ago
You have a 28.2-g sample of a metal heated to 95.2°c. you drop it in a calorimeter with 100. g of water at 25.1°c. the final tem
Vlad [161]

The heat lost by the metal should be equal to the heat gained by the water. We know that the heat capacity of water is simply 4.186 J / g °C. Therefore:

100 g * 4.186 J / g °C * (31°C – 25.1°C) = 28.2 g * Cp * (95.2°C - 31°C)

<span>Cp = 1.36 J / g °C</span>

4 0
3 years ago
Manganese, Mn, forms two ions, one with a 2+ charge and one with a 3+ charge. What is the formula for manganese (II) sulfide?
maria [59]
It would be MnSO4

The (II) lets you know it’s the form with a 2+ charge and Sulfate has a 2- charge

These will cancel out making it plain MnSO4

If it was manganese (iii) sulfide the answer would be Mn2(SO4)3
4 0
3 years ago
Question 12 (1 point)
Vinvika [58]

Answer:

Option c. Neutral

Explanation:

Only neutral solution gives a green colouration to a pH paper

8 0
3 years ago
Read 2 more answers
A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f
viva [34]

Answer: -2.373  x 10^-24J/K(particles

Explanation: Entropy is defined as the degree of randomness of a system which is a function of the state of a system and depends on the number of the random microstates present.

The entropy change for a particle in a system  depends on the initial and final states of a system and is given by Boltzmann equation as  

S = k ln(W) .

where S =Entropy

K IS Boltzmann constant ==1.38 x 10 ^-23J/K

W is the number of microstates available to the system.

 The  change in entropy is given as

S2 -S1 = kln W2 - klnW1

dS = k ln (W2/W1)

where w1 and w2 are initial and final microstates

from the question, W2(final) = 0.842 x W1(initial), so:

= 1.38*10-23 ln (0.842)

=1.38*10-23  x -0.1719

= -2.373  x 10^-24J/K(particles)

4 0
3 years ago
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