Answer:
Enthalpy of formation = -947.68KJ/mol
Explanation:
Enthalpy of formation is the heat change when one mole of a substance is formed from its element in its standard states and in standard conditions of temperature and pressure. it may be positive or negative, if positive, it is an endothermic reaction where the heat content of the product is greater than that of the reactants, and if negative, it is exothermic reaction - where the heat content of the reactants is greater than the products. the enthalpy of formation is measured in KiloJoule/Moles (KJ/Mole).
From the value of the enthalpy of formation of NaHCO3, it shows that the reaction is exothermic, that is the formation of NaHCO3 from its constituents elements. As such, the heat content of the reactants is greater than the products.
The step by step explanation is shown in the attachment.
Answer: The molar mass of the given compound is 
Explanation:
In molecular formula of 
there are two chlorine atoms and one calcium atom.
The atomic mass of the calcium = 40.07 g/mol
The atomic mass of chlorine = 35.5 g/mol
Molar mass of the guven compound is :
The molar mass of the given compound is
Answer;
-(3) an atom in an excited state
Explanation;
-An electron in a sodium atom gains enough energy to move from the second shell to the third shell. The sodium atom becomes an atom in an excited state.
-Ground state is the lowest allowable energy state of an atom. When electrons are subjected to stimuli like heat, light or electricity an electron may jump to a higher energy level, which is the excited state. Excitation is the elevation in energy level above the baseline energy state.
Answer:
To calculate the Carbon Dioxide - CO 2 - emission from a fuel, the carbon content of the fuel must be multiplied with the ratio of molecular weight of CO 2 (44) to the molecular weight of Carbon (12) -> 44 / 12 = 3.7 Emission of CO 2 from combustion of some common fuels are indicated in the table
Explanation:
Answer:
25.1 g is the mass of chlorine in the sample
Explanation:
P . V = n . R . T
We apply the Ideal Gases Law to solve the excersise.
We need to convert the T°C to T°K → 37°C + 273 = 310K
We replace data: 3 atm . 3L = n . 0.082 L.atm /mol.K . 310K
9 atm.L / (0.082 L.atm /mol.K . 310K) = n → 0.354 moles
We convert the moles to mass, to reach the answer
0.345 mol . 70.9g / 1mol = 25.1 g
