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Tom [10]
2 years ago
15

When heat is added to atoms, the molecules vibrate much more slowly.

Chemistry
1 answer:
fenix001 [56]2 years ago
3 0

Answer:

false

Explanation:

when heat  is added to atoms, the molecules vibrate more quickly, because it increases the heat energy, which in turn, increases the particle movement

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A mixture of carbon dioxide and hydrogen gases is maintained in a 6.68 L flask at a pressure of 2.14 atm and a temperature of 19
matrenka [14]

Answer:

The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>

Explanation:

<u>According to the ideal gas equation: </u>

for an ideal gas, P.V = n_{total}.R.T

and n_{total}= n_{1}+n_{2}

Here, P: total pressure of the gases = 2.14 atm  

V: total volume of the gases = 6.68 L

T: temperature = 19 °C = 19+273.15 = 292.15K        (∵ 0°C = 273.15K)

R:  gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹

n_{total}: total number of moles of gases

<u>To calculate the total number of moles of gases</u>:

n_{total} = \frac{P.V}{R.T} = \frac{2.14 atm\times 6.68 L}{0.08206 LatmK^{-}mol^{-}\times 292.15K} = <u>0.5963 moles</u>

Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂

<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g

molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol

Therefore, n_{total}= n_{1}+n_{2} =  (w₁ ÷ m₁) + (w₂ ÷ m₂)

⇒ 0.5963 mol =  (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol =  (0.3817mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)

⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)

⇒ w₂ = 0.433 g

<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>

4 0
4 years ago
Connect the group to the configuration.pleas help !!
LenaWriter [7]

Explanation:

The group number in the periodic table represents number of valence electrons of the elements in a certain group.

Group 1 : 2,8,1

Group 2 : 2,8,8,2

Group 3 : 2,8,3

Group 4: 2,4

Group 7 : 2,8,7

7 0
3 years ago
Read 2 more answers
How many formula units make up 30.4 g of magnesium chloride (mgcl2)?
ahrayia [7]
There are 1.923×10^23 formula units in 30.4g mgcl2

molar mass of mgcl2= 95.211g/mol
magnesium= 24.305g/mol
chlorine= 35.45g/mol times 2
24.305+(35.45*2)= 95.211g/mol

sample divided by molar mass times Avogadro's number gives u the formula units

30.4÷ 95.211= .31929
.3193*6.022=1.9288

3 0
4 years ago
Read 2 more answers
To find S, the number of shared
olasank [31]

Answer:

I'm rly confused but Si stands for silicon in the compound if that's what ur asking

hope it helps tho

6 0
3 years ago
Zachary adds 9.7 g to 1.114 g.<br> How many significant figures should his answer have?
makvit [3.9K]
Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs
5 0
3 years ago
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