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jasenka [17]
3 years ago
8

A conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circu

it. The bar has covered 13.00 m2 of area by a certain time and then 15.60 m2 1.00 second later. The average EMF induced in the circuit over the 1.00 second time interval is 1.30 V. What is the strength of the magnetic field?​
Physics
1 answer:
lana [24]3 years ago
6 0

Answer:

0.500 T

Explanation:

Since the change in time and the number of coils are both 1, I set the problem up to be 1.3=(1.5(x)-13(x)). I then plugged in numbers for x until I got the answer to be 1.3 V.

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A vector has an x-component
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Explanation:

The magnitude of a vector v can be found using Pythagorean's theorem.

||v|| = √(vₓ² + vᵧ²)

||v|| = √((-309)² + (187)²)

||v|| ≈ 361

You can find the angle of a vector using trigonometry.

tan θ = vᵧ / vₓ

tan θ = 187 / -309

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4 0
3 years ago
The speed of light in a vacuum is 2.99x10^8 m/s. calculate its speed in miles per hour.
34kurt
You'll never get the correct answer without the correct conversion factor. Note carefully that you have no decimal. It should be 
<span>1 km = 0.6214 miles </span>
<span>1000 m = 1 km </span>
<span>60 seconds = 1 minute </span>
<span>60 minutes = 1 hour. </span>
<span>2.998E8 m/s x (1 km/1000m) x (0.6214 miles/km) x (60 sec/min) x (60 min/hr) = ?</span>
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3 years ago
A car advertisement states that a certain car can accelerate from rest to
kaheart [24]

Answer:

a = 2.22 [m/s^2]

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The initial speed is taken as zero, as the car starts from zero.

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Answer:

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1) Increasing the current flow


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