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jasenka [17]
3 years ago
8

A conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circu

it. The bar has covered 13.00 m2 of area by a certain time and then 15.60 m2 1.00 second later. The average EMF induced in the circuit over the 1.00 second time interval is 1.30 V. What is the strength of the magnetic field?​
Physics
1 answer:
lana [24]3 years ago
6 0

Answer:

0.500 T

Explanation:

Since the change in time and the number of coils are both 1, I set the problem up to be 1.3=(1.5(x)-13(x)). I then plugged in numbers for x until I got the answer to be 1.3 V.

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Answer:

948.15248\ N

5134.04751\ N

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As the forces are conserved we have

(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N

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The force on each rear whees is \dfrac{1896.30497}{2}=948.15248\ N

Force on each front wheel is \dfrac{10268.09503}{2}=5134.04751\ N

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