Answer:
it means that velocity of a body rises by 9.8m/s each second if the air resistance is nrelated
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Explanation:
It is given that,
Mass of the box, m = 100 kg
Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.
From the attached figure, the x and y component of forces is given by :
Let and is the resultant in x and y direction.
As the system is balanced the net force acting on it is 0. So,
.............(1)
..................(2)
On solving equation (1) and (2) we get:
(tension on the left rope)
(tension on the right rope)
So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.
The solution would be like
this for this specific problem:
V^2 = 2AS = 2FS/M
V = sqrt(2FS/M) =
sqrt(2*105*.75/.087) = 44.52817783 = 42.5 mps
So the speed of the arrow as it leaves the bow
is 42.5 mps.
I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
Answer: 5.79 s
Explanation:
Vs=0 m/s starting speed(from rest)
Vf=325 km/h= 325*1000/3600= 90.28 m/s
a=15.6m/s²
Using equation for acceleration we can find out time :
a=(Vf-Vs)/t
t=(Vf-Vs)/a
t=(90.28 m/s-0m/s)/15.6 m/s²
t=5.79 s
Answer:
Explanation:
The x- and y- components of the velocity vector can be written as following:
Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows: