2 years ago

Whats the velocity of a ball falling with 100joules of kinetic energy and a mass of 2 kilograms?

1 answer:

5 0

Short answer: v = 10 m/s
Comment
This is just an application of KE = 1/2 m v^2
Givens
KE = 100 Joules
m = 2 kg
v = ???

Formula
KE = 1/2 m v^2

Substitution and Solve
100 = 1/2 * 2 * v^2
100 = v^2 Take the square root of both sides.
sqrt(100) = sqrt(v^2)
v = 10 m/s

Comment
There is no KE unless v > 0.
You may have PE when v = 0, but not KE.

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The force F⃗ pulling the string is constant; therefore the magnitude of the angular acceleration α of the wheel is constant for

abruzzese [7]

Answer:

The answer is " $\boxed{\boxed{\omega = \sqrt{\frac{2fd}{kmr^2}}}}$ "

Explanation:

$\to d= r \theta \\\\ \to \theta =\frac{d}{r}\\\\\to \omega^{r} - \omega_{0}^{r} = 2 \alpha \theta\\\\\to \omega^{r} = 2 \alpha \theta - \omega_{0}^{r} \\\\\to \omega^{r} = 2 (\frac{F}{Kmr}) \frac{d}{r}\\\\\to \omega = \sqrt{\frac{2fd}{kmr^2}}$