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SashulF [63]
3 years ago
7

A basketball player can jump 1.6 m off the hardwood floor. With what upward velocity did he leave the floor?

Physics
2 answers:
just olya [345]3 years ago
6 0

Answer:

The upward velocity is 5.6 m/s.

(5) is correct option.

Explanation:

Given that,

Height = 1.6 m

We need to calculate the the upward velocity

Using equation of motion

v^2=u^2-2gh

u=\sqrt{2gh}

Here, g = acceleration due to gravity

v = final velocity

u = initial velocity

h = height

Put the value into the formula

u=\sqrt{2\times9.8\times1.6}

u=5.6\ m/s

Hence,  The upward velocity is 5.6 m/s.

irinina [24]3 years ago
3 0
First do 1.6 m (how far he jumps) 9.8 m/s (what gravity is measured at) then times 2

= 31.36

Sq root = 5.6
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