Question

A basketball player can jump 1.6 m off the hardwood floor. With what upward velocity did he leave the floor?

Answer 1

Answer:

The upward velocity is 5.6 m/s.

(5) is correct option.

Explanation:

Given that,

Height = 1.6 m

We need to calculate the the upward velocity

Using equation of motion

$v^2=u^2-2gh$

$u=\sqrt{2gh}$

Here, g = acceleration due to gravity

v = final velocity

u = initial velocity

h = height

Put the value into the formula

$u=\sqrt{2\times9.8\times1.6}$

$u=5.6\ m/s$

Hence,  The upward velocity is 5.6 m/s.

Answer 2

First do 1.6 m (how far he jumps) 9.8 m/s (what gravity is measured at) then times 2

= 31.36

Sq root = 5.6