The work done by Sarah is 3000 J
Explanation:
The work done by Sarah in climbing the set of stairs up is equal to its change in gravitational potential energy, and it is given by:
where:
F is Sarah's weight
d is the vertical distance covered by Sarah
In this problem, we have:
F = 500 N is Sarah's weight
d = 6 m is the vertical distance covered by Sarah
Substituting, we find the work done:
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Answer:
Entropy is increasing. Entropy is decreasing.
Explanation:
The Entropy doesn't change.
The kinetic energy of the proton is 1982.31 MeV.
We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by
Eo = m₀ . c²
where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).
The total energy of object can be described as
E = Eo / √(1 - v²/c²)
where E is total energy, v is the object speed.
Kinetic energy can be defined as energy change from rest energy until total energy. It can be determined as
KE = E - Eo
where KE is kinetic energy.
From the question above, we know that :
m₀ = 1.6 x 10¯²⁷ kg
c = 3 x 10⁸ m/s
v = 0.95c
Find the rest energy
Eo = m₀ . c²
Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²
Eo = 1.44 x 10¯¹⁰ joule
Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV
Eo = 900 x 10⁶ eV
Eo = 900 MeV
Determine the total energy
E = Eo / √(1 - v²/c²)
E = 900 / √(1 - (0.95c)²/c²)
E = 900 / 0.31
E = 2882.31 MeV
Calculate the kinetic energy
KE = E - Eo
KE = 2882.31 MeV - 900 MeV
KE = 1982.31 MeV
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Rubbing converts neutrons to protons, increasing the charge (APEX)
Answer:
The distance of the runners from the flag pole is 1.28 miles west of the flagpole
Explanation:
Both the runners will meet at the same time = t
Distance they will cover together = 7 + 1 = 8 miles
Let speed of runner A = v₁ = 5 mph
Let speed of runner B = v₂ = 2 mph
Distance = Speed × Time
v₁t+v₂t = 8
Distance covered by runner A = v₁t = 5× (8/7) = 5.71 miles
Distance of runner A from flagpole = 7-5.71 = 1.28
The distance of the runners from the flag pole is 1.28 miles west of the flagpole.