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Lina20 [59]
3 years ago
10

To clean the outside of your house you rent a small high-pressure water sprayer. The sprayer’s pump delivers slow-moving water a

t a pressure of 9000000.0 Pa (about 90.0 atmospheres). How fast can this water move if all of its pressure potential energy becomes kinetic energy as it flows through the nozzle of the sprayer?
Physics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

Velocity is 134.16 m/s

Explanation:

Slow moving water pressure is the dynamic pressure. Dynamic pressure is actually the kinetic energy per unit volume of a fluid particle. It is equal to the difference between stagnation pressure and static pressure and also can be derived from Bernoulli's equation.

Formula for Dynamic Pressure (P) is

               P = 0.5 d v²

Where d is density of fluid and v is the velocity.

Density of water = 1000 kg/m³

P = 9000000 Pa

V = ?

                      P = 0.5 d v²  

         9000000 = 0.5 × 1000 × v²

                       v = √(9000000 ÷ 500)

                       v = 134.16 m/s

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Which of these is a likely impact of stronger than normal trade winds on the eastern Pacific Ocean?
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Jet stream would be displaced southwards causing heavy rain and flooding.

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What is the heat flux (W/m^2), due to radiation heat transfer, from a black body if the surface temperature is 1000C? The convec
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55000 W/m²

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Hence, Heat Flux, q, is given as:

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An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

x = V*t = -8\frac{m}{s} *3s = -24m

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

v^2 = v_0^2 + 2a*d

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s

Then, the time of the second phase will be:

t_2 = 9s - t_1 = 9s - 1.143s = 7.857s

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

x = \frac{1}{2}a*t^2 + v_0*t + x_0

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m

So, the total distance covered by this object in meters will be the sum of all the distances we found:

x_total = 24m + 4.57m + 216.07m = 244.64m

8 0
3 years ago
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