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Lina20 [59]
3 years ago
10

To clean the outside of your house you rent a small high-pressure water sprayer. The sprayer’s pump delivers slow-moving water a

t a pressure of 9000000.0 Pa (about 90.0 atmospheres). How fast can this water move if all of its pressure potential energy becomes kinetic energy as it flows through the nozzle of the sprayer?
Physics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

Velocity is 134.16 m/s

Explanation:

Slow moving water pressure is the dynamic pressure. Dynamic pressure is actually the kinetic energy per unit volume of a fluid particle. It is equal to the difference between stagnation pressure and static pressure and also can be derived from Bernoulli's equation.

Formula for Dynamic Pressure (P) is

               P = 0.5 d v²

Where d is density of fluid and v is the velocity.

Density of water = 1000 kg/m³

P = 9000000 Pa

V = ?

                      P = 0.5 d v²  

         9000000 = 0.5 × 1000 × v²

                       v = √(9000000 ÷ 500)

                       v = 134.16 m/s

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<h2>Answers:</h2>

<h2>(a) </h2>

According to Newton's Law of Gravitation, the Gravity Force is:

F=\frac{GMm}{{r}^{2}}     (1)

This expression can also be written as:

F=GMm{r}^{-2}    (2)

If we derive this force F respect to the distance r between the two masses:

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Taking into account GMm are constants:

\frac{dF}{dr}dFdr=-2GMm{r}^{-3}     (4)

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In other words, this means how much does the Gravity Force changes with the distance between the two bodies.

More precisely this change is inversely proportional to the distance elevated to the cubic exponent.

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<h2>(c) The minus sign indicates that the bodies are being forced in the negative direction.  </h2>

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<h2>(d) </h2>

In the first answer we already found the decrease rate of the Gravity force respect to the distance, being its unit N/km:

\frac{dF}{dr}dFdr=-2\frac{GMm}{{r}^{3}}     (5)

We have a force that decreases with a rate 1 \frac{dF_{1}}{dr}dFdr=4N/km when r=20000km:

4N/km=-2\frac{GMm}{{(20000km)}^{3}}     (6)

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XN/km=-2\frac{GMm}{{(10000km)}^{3}}     (8)

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X=\frac{4N/km)({(20000km)}^{3}}{{(10000km)}^{3}}  

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